Assuming you started with 3.23 g of sodium bicarbonate and your actual yield of solid product is 1.20g, which reaction is more likely to be the correct one?

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Assuming you started with 3.23 g of sodium bicarbonate and your actual yield of solid product is 1.20g, which reaction is more likely to be the correct one?

 

Balance each of the following: (please add 1 where needed - even though we usually do not)
1) 1
NaHCO3 (s) ----> 1
2) 2
NaHCO3 (s) ---
---->
1
1
H2O(g)
+
3) 2
NaHCO3 (s)---> 1
1
4) 2
NaHCO3 (s)---
1
H2(g) +
2
C(s) + 3
O2(g)
Using a mass of 5.48 g baking soda you started with initially, calculate the mass (g) of solid product that should be produced for equation 3 above. Answer with two decimal
places and do not include units. Please use: Na = 22.99; H = 1.008; C = 12.011 and O= 15.999 g/mole.
Using a mass of 1.01 g baking soda you started with initially, calculate the mass (g) of solid product that should be produced for equation 4 above. Answer with two decimal
places and do not include units. Please use: Na = 22.99; H = 1.008; C = 12.011 and O = 15.999 g/mole.
H₂O(g)
----> 2
NaOH (s)
+
Na2CO3(s) +
+
Na(s) +
Na2O(s)
1
1
CO2(g)
CO2(g)
CO2(g)
+
Transcribed Image Text:Balance each of the following: (please add 1 where needed - even though we usually do not) 1) 1 NaHCO3 (s) ----> 1 2) 2 NaHCO3 (s) --- ----> 1 1 H2O(g) + 3) 2 NaHCO3 (s)---> 1 1 4) 2 NaHCO3 (s)--- 1 H2(g) + 2 C(s) + 3 O2(g) Using a mass of 5.48 g baking soda you started with initially, calculate the mass (g) of solid product that should be produced for equation 3 above. Answer with two decimal places and do not include units. Please use: Na = 22.99; H = 1.008; C = 12.011 and O= 15.999 g/mole. Using a mass of 1.01 g baking soda you started with initially, calculate the mass (g) of solid product that should be produced for equation 4 above. Answer with two decimal places and do not include units. Please use: Na = 22.99; H = 1.008; C = 12.011 and O = 15.999 g/mole. H₂O(g) ----> 2 NaOH (s) + Na2CO3(s) + + Na(s) + Na2O(s) 1 1 CO2(g) CO2(g) CO2(g) +
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