At 25°C the molar volume of water V is given by: V= 18.066-7.15 X 10-4 P + 4.6 X 10-8 P2 where V is in cm3 /mol and P is in atm for Pressure between 0 and 1000 atm and ( dV/dT )p= 0.0045+1.4 x 10-6P(Cm3 K/mol) Determine the work necessary at 25 °C to compress 1 mol of water from 1 atm to 1000 atm and the change in its internal energy.
At 25°C the molar volume of water V is given by: V= 18.066-7.15 X 10-4 P + 4.6 X 10-8 P2 where V is in cm3 /mol and P is in atm for Pressure between 0 and 1000 atm and ( dV/dT )p= 0.0045+1.4 x 10-6P(Cm3 K/mol) Determine the work necessary at 25 °C to compress 1 mol of water from 1 atm to 1000 atm and the change in its internal energy.
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter4: Energy And Chemical Reactions
Section: Chapter Questions
Problem 96QRT
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At 25°C the molar volume of water V is given by:
V= 18.066-7.15 X 10-4 P + 4.6 X 10-8 P2
where V is in cm3 /mol and P is in atm for Pressure between 0 and 1000 atm and
( dV/dT )p= 0.0045+1.4 x 10-6P(Cm3 K/mol)
Determine the work necessary at 25 °C to compress 1 mol of water from 1 atm to 1000 atm and the change in its internal energy.
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Transcribed Image Text:Q.5
At 25°C the molar volume of water V is given by:
V = 18.066 – 7.15 X 10ª P + 4.6 X 10-8 P²,
where V is in cm/mol and P is in atm for Pressure between 0 and 1000 atm and
Ст3
0.0045 + 1.4 × 10-6P (–. K)
mol
%3D
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Determine the work necessary at 25 °C to compress 1 mol of water from 1 atm to
1000 atm and the change in its internal energy.
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