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At 25°C the molar volume of water V is given by: V = 18.066 – 7.15 X 10ª P + 4.6 X 108 P², where V is in cm?/mol and P is in atm for Pressure between 0 and 1000 atm and (av Ст3 = 0.0045 + 1.4 x 10-6P - .K) mol Determine the work necessary at 25 °C to compress 1 mol of water from 1 atm to 1000 atm and the change in its internal energy.

At 25°C the molar volume of water V is given by: V = 18.066 – 7.15 X 10ª P + 4.6 X 108 P², where V is in cm?/mol and P is in atm for Pressure between 0 and 1000 atm and (av Ст3 = 0.0045 + 1.4 x 10-6P - .K) mol Determine the work necessary at 25 °C to compress 1 mol of water from 1 atm to 1000 atm and the change in its internal energy.

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Q.5 At 25°C the molar volume of water V is given by: V = 18.066 – 7.15 X 10ª P + 4.6 X 108 P², where V is in cm/mol and P is in atm for Pressure between 0 and 1000 atm and Ст3 . К) `mol = 0.0045 + 1.4 × 10-6P ƏT, Determine the work necessary at 25 °C to compress 1 mol of water from 1 atm to 1000 atm and the change in its internal energy.
Transcribed Image Text:Q.5 At 25°C the molar volume of water V is given by: V = 18.066 – 7.15 X 10ª P + 4.6 X 108 P², where V is in cm/mol and P is in atm for Pressure between 0 and 1000 atm and Ст3 . К) `mol = 0.0045 + 1.4 × 10-6P ƏT, Determine the work necessary at 25 °C to compress 1 mol of water from 1 atm to 1000 atm and the change in its internal energy.
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