At 25°C, the standard enthalpy of formation of HF(aq) is -319.9 kJ/mol. Of OH (aq), it is -229.5 kJ/mol. Of F (aq), it is -330.3 kJ/mol, and of H20(1), it is -285.2 kJ/mol. (a) Calculate the standard enthalpy of neutralization of HF(aq): HF(aq) + OH (aq) F (aq) + H,0(1) kJ/mol (b) Using the value of-56.2 kJ as the standard enthalpy change for the reaction H*(aq) + OH (aq → H20(1) calculate the standard enthalpy change for the reaction HF(aq) H*(aq) +F (aq) kJ/mol

Chemistry: An Atoms First Approach
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Author:Steven S. Zumdahl, Susan A. Zumdahl
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Chapter7: Chemical Energy
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Problem 76E: Write reactions for which the enthalpy change will be a. Hf for solid aluminum oxide. b. the...
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At 25°C, the standard enthalpy of formation of HF(aq) is -319.9 kJ/mol. Of OH (aq), it is
-229.5 kJ/mol. Of F (aq), it is -330.3 kJ/mol, and of H20(1), it is -285.2 kJ/mol.
(a) Calculate the standard enthalpy of neutralization of HF(aq):
HF(aq) + OH¯(aq)F (aq) + H2O(1)
kJ/mol
(b) Using the value of-56.2 kJ as the standard enthalpy change for the reaction
H*(aq) + OH (aq → H2O(1)
calculate the standard enthalpy change for the reaction
HF(aq) → H*(aq) + F (aq)
kJ/mol
Transcribed Image Text:At 25°C, the standard enthalpy of formation of HF(aq) is -319.9 kJ/mol. Of OH (aq), it is -229.5 kJ/mol. Of F (aq), it is -330.3 kJ/mol, and of H20(1), it is -285.2 kJ/mol. (a) Calculate the standard enthalpy of neutralization of HF(aq): HF(aq) + OH¯(aq)F (aq) + H2O(1) kJ/mol (b) Using the value of-56.2 kJ as the standard enthalpy change for the reaction H*(aq) + OH (aq → H2O(1) calculate the standard enthalpy change for the reaction HF(aq) → H*(aq) + F (aq) kJ/mol
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