At 298 K, the Henry's law constant for oxygen is 0.00130 M/atm. Air is 21.0% oxygen. At 298 K, what is the solubility of oxygen in water exposed to air at 1.00 atm? solubility: M At 298 K, what is the solubility of oxygen in water exposed to air at 0.900 atm? solubility: M If atmospheric pressure suddenly changes from 1.00 atm to 0.900 atm at 298 K, how much oxygen will be released from 4.50 L of water in an unsealed container? amount: mol

Chemistry by OpenStax (2015-05-04)
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Chapter13: Fundamental Equilibrium Concepts
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At 298 K, the Henry's law constant for oxygen is 0.00130 M/atm. Air is 21.0% oxygen.
At 298 K, what is the solubility of oxygen in water exposed to air at 1.00 atm?
solubility:
M
At 298 K, what is the solubility of oxygen in water exposed to air at 0.900 atm?
solubility:
M
If atmospheric pressure suddenly changes from 1.00 atm to 0.900 atm at 298 K, how much oxygen will be released from 4.50 L
of water in an unsealed container?
amount:
mol
Transcribed Image Text:At 298 K, the Henry's law constant for oxygen is 0.00130 M/atm. Air is 21.0% oxygen. At 298 K, what is the solubility of oxygen in water exposed to air at 1.00 atm? solubility: M At 298 K, what is the solubility of oxygen in water exposed to air at 0.900 atm? solubility: M If atmospheric pressure suddenly changes from 1.00 atm to 0.900 atm at 298 K, how much oxygen will be released from 4.50 L of water in an unsealed container? amount: mol
Expert Solution
Step 1

Given:

KH of O2=0.00130 M/atmPressure=1 atmTemperature=298 KVolume=4.50 L

 

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