At 298K, the equilibrium constant for the following reaction is 5.90×102: H2C204(aq) + H2O= H30*(aq) + HC204 (aq) The equilibrium constant for a second reaction is 6.40x105: HC204 (aq) + H20= H30*(aq) + C204² (aq) Use this information to determine the equilibrium constant for the reaction: H2C204(aq) + 2H2O= 2H30*(aq) + C2042¯(aq) K =

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter14: Chemical Equilibrium
Section: Chapter Questions
Problem 16P
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The equilibrium constant, Kc, for the following reaction is 2.90×102 at 1150 K.
2503(g) 2s02(g) + 02(g)
Calculate Kc at this temperature for:
2502(g) + 02(g) =2503(g)
Kc =
Transcribed Image Text:The equilibrium constant, Kc, for the following reaction is 2.90×102 at 1150 K. 2503(g) 2s02(g) + 02(g) Calculate Kc at this temperature for: 2502(g) + 02(g) =2503(g) Kc =
At 298K, the equilibrium constant for the following reaction is 5.90×102:
H2C204(aq) + H2O= H30*(aq) + HC204 (aq)
The equilibrium constant for a second reaction is 6.40x105:
HC204 (aq) + H20= H30*(aq) + C204² (aq)
Use this information to determine the equilibrium constant for the reaction:
H2C204(aq) + 2H2O= 2H30*(aq) + C2042¯(aq)
K =
Transcribed Image Text:At 298K, the equilibrium constant for the following reaction is 5.90×102: H2C204(aq) + H2O= H30*(aq) + HC204 (aq) The equilibrium constant for a second reaction is 6.40x105: HC204 (aq) + H20= H30*(aq) + C204² (aq) Use this information to determine the equilibrium constant for the reaction: H2C204(aq) + 2H2O= 2H30*(aq) + C2042¯(aq) K =
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