At high concentrations of [H2] the observed rate law is found to change to the form: Rate = k[NO]? i.e. the rate becomes independent of [H2]. Assess whether the two step mechanism that you showed to be plausible at lower[H2] concentrations in the pre- problem can also explain this additional data. Reexamine the mechanism in the Pre-recitation Problem: 2NO + H2 → O + H20 + N2 slow ki 0 + H2 → H2O k2 Write the forward rates for both steps.

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter11: Chemical Kinetics: Rates Of Reactions
Section11.3: Rate Law And Order Of Reactions
Problem 11.4PSP
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Topic VII Problem Manipulation
At high concentrations of [H2] the observed rate law is found to change to the form:
Rate = k[NO]? ie. the rate becomes independent of [H2]. Assess whether the two step
mechanism that you showed to be plausible at lower[H2] concentrations in the pre-
problem can also explain this additional data.
Reexamine the mechanism in the Pre-recitation Problem:
2NO + H2 → O+ H2O+ N2 slow ki
0+ H2 → H2O
k2
Write the forward rates for both steps.
Based on these rates, would you expect the mechanism to change as [H2] increases?
(Hint look at the ratio)
Can this mechanism give the rate law Rate = k[NO]² observed at high [H2]?
Transcribed Image Text:Topic VII Problem Manipulation At high concentrations of [H2] the observed rate law is found to change to the form: Rate = k[NO]? ie. the rate becomes independent of [H2]. Assess whether the two step mechanism that you showed to be plausible at lower[H2] concentrations in the pre- problem can also explain this additional data. Reexamine the mechanism in the Pre-recitation Problem: 2NO + H2 → O+ H2O+ N2 slow ki 0+ H2 → H2O k2 Write the forward rates for both steps. Based on these rates, would you expect the mechanism to change as [H2] increases? (Hint look at the ratio) Can this mechanism give the rate law Rate = k[NO]² observed at high [H2]?
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