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At one instant a bicyclist is 40.0 m due east of a park's flagpole, going due south with a speed of 11.0 m/s. Then 37.0 s later, the cyclist is 40.0 m due north of the flagpole, going due east with a speed of 11.0 m/s. For the cyclist in this 37.0 s interval, what are the (a) magnitude and (b) direction of the displacement, the (c) magnitude and (d) direction of the average velocity, and the (e) magnitude and (f) direction of the average acceleration? (Give all directions as positive angles relative to due east, where positive is meaured going counterclockwise.)

Question

At one instant a bicyclist is 40.0 m due east of a park's flagpole, going due south with a speed of 11.0 m/s. Then 37.0 s later, the cyclist is 40.0 m due north of the flagpole, going due east with a speed of 11.0 m/s. For the cyclist in this 37.0 s interval, what are the (a) magnitude and (b) direction of the displacement, the (c) magnitude and (d) direction of the average velocity, and the (e) magnitude and (f) direction of the average acceleration? (Give all directions as positive angles relative to due east, where positive is meaured going counterclockwise.)

check_circleAnswer
Step 1

(a) Displacement is given by,

(40m+(40m
|지 = V-(40m) +(40m):
-56.56m
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Image Transcriptionclose

(40m+(40m |지 = V-(40m) +(40m): -56.56m

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Step 2

(b) Direction is,

40m
e=tan
-40m
(from + xaxis)
1350
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Image Transcriptionclose

40m e=tan -40m (from + xaxis) 1350

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Step 3

(c) Average velo...

|x|
Δt
56.56m
37.0s
=1.53m/s
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Image Transcriptionclose

|x| Δt 56.56m 37.0s =1.53m/s

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