At the 0.05 significance level, test the claim for the modified components, the mean time, between failures is greater than 520 hours. Assume that a simple random sample has been selected from a normally distributedpopulation and test the given claim. Use either the traditional method or P-value methodas indicated. Identify the null and alternative hypotheses, test statistic, critical value(s) orP-value (or range of P-values) as appropriate, and state the final conclusion thataddresses the original claim. Choose the correct option based on the probleminformation.In tests of a computer component, it is found that the mean time between failures is 520 hours.A modification is made which is supposed to increase the time between failures. Tests on arandom sample of 10 modified components resulted in the following times (in hours) betweenfailures.518 548 561 523 536499 538 557 528 5635At the 0.05 significance level, test the claim that for the modified components, the mean timebetween failures is greater than 520 hours. Use the P-value method of testing hypotheses.Choose the correct P-value and conclusion based on the null hypothesis0.01 < P-value <0.025. Reject H00.05 < P-value <0.1. Reject H₂00.01 < P-value < 0.025. Fail to reject H0.1 < P-value <0.2. Reject Ho.

The hypothesized mean is 14 oz.

Answered: At the 0.05 significance level, test…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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At the 0.05 significance level, test the claim for the modified components, the mean time, between failures is greater than 520 hours.

Assume that a simple random sample has been selected from a normally distributed
population and test the given claim. Use either the traditional method or P-value method
as indicated. Identify the null and alternative hypotheses, test statistic, critical value(s) or
P-value (or range of P-values) as appropriate, and state the final conclusion that
addresses the original claim. Choose the correct option based on the problem
information.
In tests of a computer component, it is found that the mean time between failures is 520 hours.
A modification is made which is supposed to increase the time between failures. Tests on a
random sample of 10 modified components resulted in the following times (in hours) between
failures.
518 548 561 523 536
499 538 557 528 563
5
At the 0.05 significance level, test the claim that for the modified components, the mean time
between failures is greater than 520 hours. Use the P-value method of testing hypotheses.
Choose the correct P-value and conclusion based on the null hypothesis
0.01 < P-value <0.025. Reject H
00.05 < P-value <0.1. Reject H₂
00.01 < P-value < 0.025. Fail to reject H
0.1 < P-value <0.2. Reject Ho.

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

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