(b) Lead(II) nitrate +potassium brom 4.47 If 38.5 mL of lead(II) nitrate solution reacts completely with excess sodium iodide solution to yield 0.628 g of precipitate, what is the molarity of lead(II) ion in the original solution? ss notas-

Principles of Modern Chemistry
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Chapter15: Acid–base Equilibria
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(b) Lead(II) nitrate +potassium brom
4.47 If 38.5 mL of lead(II) nitrate solution reacts completely with
excess sodium iodide solution to yield 0.628 g of precipitate, what
is the molarity of lead(II) ion in the original solution?
ss notas-
Transcribed Image Text:(b) Lead(II) nitrate +potassium brom 4.47 If 38.5 mL of lead(II) nitrate solution reacts completely with excess sodium iodide solution to yield 0.628 g of precipitate, what is the molarity of lead(II) ion in the original solution? ss notas-
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