(b) Use rules of varlance to obtain an expressilon for the varlance and standard devlation (standard error) of theestimator In part (a).V(X – ) = V(X) + V()đx - y VV(X – nCompute the estimated standard error. (Round your answer to three decimal places.)MPa(c) Calculate a point estimate of the ratio a,/a, of the two standard deviations. (Round your answer to threedecimal places.)(d) Suppose a single beam and a single cylinder are randomly selected. Calculate a point estimate of the varianceof the difference X - Y between beam strength and cylinder strength. (Round your answer to two decimal places.)MPa? Consider the accompanying data on flexural strength (MPa) for concrete beams of a certaln type.5.7 7.2 7.3 6.3 8.1 6.8 7.0 7.6 6.86.57.06.3 7.9 9.09.0 8.7 7.8 9.7 7.4 7.7 9.7 8.0 7.7 11.6 11.3 11.8 10.7The data below give accompanying strength observations for cylinders.6.5 5.8 7.8 7.1 7.2 9.2 6.68.37.08.57.6 8.1 7.4 8.5 8.9 9.8 9.7 14.1 12.6 11.9Prior to obtaining data, denote the beam strengths by X, .., X, and the cylinder strengths by Y,...,Y,. Supposethat the X's constitute a random sample from a distribution with mean u, and standard devlation a, and that the Y/s forma random sample (Independent of the X's) from another distribution with mean H, and standard deviation a.(a) Use rules of expected value to show that X - Y is an unblased estimator of jH, - H.O E(X - ) -E(X) - E(Y)H1 - H2nmO ECX - Y) - (E(X) – E(Yn) - Hy - MzO ECX - ) - E(X) – E(Y) = Hi - HzO E(X – Y) = VE(X) – E(Y) = Hy - HzO ECX – Y) = nm( E(X) – E(Y) = Hy - H2Calculate the estimate for the given data. (Round your answer to three decimal places.)MPa

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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An agent for a property management company would like to be able to predict the monthly rental cost for apartments based on the size of the apartment as defined by square footage. A sample of the rent of 25 apartments in a college rental neighborhood was selected, and the information collected revealed the following: Apartment Size (Sq. Ft.) Monthly Rent ($) 1 850 950 2 1,450 1,600 3 1,085 1,200 4 1,232 1,500 5 718 950 6 1,485 1,700 7 1,136 1,650 8 726 935 9 700 875 10 956 1,150 11 1,100 1,400 12 1,285 1,650 13 1,985 2,300 14 1,369 1,800 15 1,175 1,400 16 1,225 1,450 17 1,245 1,100 18 1,259 1,700 19 1,150 1,200 20 896 1,150 21 1,361 1,600 22 1,040 1,650 23 755 1,200 24 1,000 800 25 1,200 1,750 e) Determine the coefficient of determination r2 and then completely interpret…
An agent for a property management company would like to be able to predict the monthly rental cost for apartments based on the size of the apartment as defined by square footage. A sample of the rent of 25 apartments in a college rental neighborhood was selected, and the information collected revealed the following: Apartment Size (Sq. Ft.) Monthly Rent ($) 1 850 950 2 1,450 1,600 3 1,085 1,200 4 1,232 1,500 5 718 950 6 1,485 1,700 7 1,136 1,650 8 726 935 9 700 875 10 956 1,150 11 1,100 1,400 12 1,285 1,650 13 1,985 2,300 14 1,369 1,800 15 1,175 1,400 16 1,225 1,450 17 1,245 1,100 18 1,259 1,700 19 1,150 1,200 20 896 1,150 21 1,361 1,600 22 1,040 1,650 23 755 1,200 24 1,000 800 25 1,200 1,750 i) Determine a 95% interval estimate for the average rent of apartments with 1000…
A statistical program is recommended. An article gave the data, shown in the table below, on dimensions of 27 representative food products. Product Material Height MaximumWidth MinimumWidth Elongation Volume 1 glass 7.7 2.50 1.80 1.50 120 2 glass 6.2 2.90 2.70 1.07 140 3 glass 8.5 2.15 2.00 1.98 175 4 glass 10.4 2.90 2.60 1.79 290 5 plastic 8.0 3.20 3.15 1.25 334 6 glass 8.7 2.00 1.80 2.17 87 7 glass 10.2 1.60 1.50 3.19 118 8 plastic 10.5 4.80 3.80 1.09 520 9 plastic 3.4 5.90 5.00 0.29 333 10 plastic 6.9 5.80 4.75 0.59 568 11 tin 10.9 2.90 2.80 1.88 337 12 plastic 9.7 2.45 2.10 1.98 173 13 glass 10.1 2.60 2.20 1.94 245 14 glass 13.0 2.60 2.60 2.50 238 15 glass 13.0 2.70 2.60 2.41 359 16 glass 11.0 3.10 2.90 1.77 305 17 cardboard 8.7 5.10 5.10 0.85 636 18 cardboard 17.1 10.20 10.20 0.84 1255 19 glass 16.5 3.50 3.50 2.36 649 20 glass 16.5 2.70 1.20 3.06 304 21 glass 9.7 3.00 1.70 1.62 310 22 glass 17.8 2.70 1.75 3.30 309 23 glass 14.0 2.50…
STATE: How heavy a load (in pounds) is needed to pull apart pieces of Douglas fir 4 inches long and 1.5 inches square? Given are data from students doing a laboratory exercise. 33,190 31,860 32,590 26,520 33,280 32,320 33,020 32,030 30,460 32,700 23,040 30,930 32,720 33,650 32,340 24,050 30,170 31,300 28,730 31,920 We are willing to regard the wood pieces prepared for the lab session as an SRS of all similar pieces of Douglas fir. Engineers also commonly assume that characteristics of materials vary Normally. Suppose that the strength of pieces of wood like these follows a Normal distribution with standard deviation 3000 pounds. PLAN: We will estimate ? by giving a 98% confidence interval. SOLVE: Find the sample mean ?¯ . (Enter your answer rounded to the nearest whole number.) ?¯= Give a 98% confidence interval, [???,ℎ??ℎ] , for the mean load required to pull the wood apart. (Enter your answers rounded to the nearest whole number.) ???=…
Consider the accompanying data on flexural strength (MPa) for concrete beams of a certain type. 5.3 7.2 7.3 6.3 8.1 6.8 7.0 7.1 6.8 6.5 7.0 6.3 7.9 9.0 9.0 8.7 7.8 9.7 7.4 7.7 9.7 7.9 7.7 11.6 11.3 11.8 10.7 The data below give accompanying strength observations for cylinders. 6.8 5.8 7.8 7.1 7.2 9.2 6.6 8.3 7.0 9.0 7.6 8.1 7.4 8.5 8.9 9.8 9.7 14.1 12.6 11.8 Prior to obtaining data, denote the beam strengths by X1, . . . , Xm and the cylinder strengths by Y1, . . . , Yn. Suppose that the Xi's constitute a random sample from a distribution with mean ?1 and standard deviation ?1 and that the Yi's form a random sample (independent of the Xi's) from another distribution with mean ?2 and standard deviation ?2. (a) Calculate the estimate for the given data. (Round your answer to three decimal places.) (b) Use rules of variance to obtain an expression for the variance and standard deviation (standard error) of the estimator in part (a). V(X − Y) = V(X) + V(Y) =…
Consider the accompanying data on flexural strength (MPa) for concrete beams of a certain type. 5.5 7.2 7.3 6.3 8.1 6.8 7.0 7.2 6.8 6.5 7.0 6.3 7.9 9.0 8.7 8.7 7.8 9.7 7.4 7.7 9.7 8.0 7.7 11.6 11.3 11.8 10.7 The data below give accompanying strength observations for cylinders. 6.6 5.8 7.8 7.1 7.2 9.2 6.6 8.3 7.0 8.4 7.3 8.1 7.4 8.5 8.9 9.8 9.7 14.1 12.6 11.3 Prior to obtaining data, denote the beam strengths by X1, . . . , Xm and the cylinder strengths by Y1, . . . , Yn. Suppose that the Xi's constitute a random sample from a distribution with mean μ1 and standard deviation σ1 and that the Yi's form a random sample (independent of the Xi's) from another distribution with mean μ2 and standard deviation σ2. Compute the estimated standard error. (Round your answer to three decimal places.) (c) Calculate a point estimate of the ratio σ1/σ2 of the two standard deviations. (Round your answer to three decimal places.) (d) Suppose a single beam and a single cylinder are…
Construct a hypothesis addressing which potato piece will have the greatest surface-area-to-volume ratio. Explain. Table 1a Why Are Cells Small Length (l) (cm) Width (w) (cm) Height (h) (cm) Size of Cross Section (h x w) (cm) Distance Traveled by IKI from Potato Edge (cm) Area of White Region (l x w) (cm) 2.50 2.50 2.50 6.25 cm 0.20 cm 2.64 cm 2.00 2.00 1.00 2.00cm 0.30 cm 1.87 cm 1.50 1.50 1.50 2.25 cm 0.50 cm 1.50 cm 1.00 1.00 1.00 1.00 cm 0.40 0.60 cm 2.00 0.50 0.50 0.25 cm 0.20 cm 0.15 cm 0.50 0.50 0.50 0.25 cm 0.30 cm 0.10 cm
In a summary report given by Ing. Pobbi on the lengths of ironrods produced by two machines, he stated that the variability ofmachine A was higher compared to that of machine B. Critiquethe report of the Engineer given data on the length of rodsproduced given as; MachineA(cm): 380 410 280 310 305 360 270 355 400 Machine B(m): 1.1 1.3 1.2 2.0 1.5 1.6 1.4 1.6 1.7
STATE: How heavy a load (in pounds) is needed to pull apart pieces of Douglas fir 44 inches long and 1.5 inches square? Given are data from students doing a laboratory exercise. 33,190 31,860 32,590 26,520 33,280 32,320 33,020 32,030 30,460 32,700 23,040 30,930 32,720 33,650 32,340 24,050 30,170 31,300 28,730 31,920 We are willing to regard the wood pieces prepared for the lab session as an SRS of all similar pieces of Douglas fir. Engineers also commonly assume that characteristics of materials vary Normally. Suppose that the strength of pieces of wood like these follows a Normal distribution with standard deviation 3000 pounds. PLAN: We will estimate μ by giving a 95% confidence interval. SOLVE: Find the sample mean x¯ . (Enter your answer rounded to the nearest whole number.) x¯= Give a 95% confidence interval, [low, high] , for the mean load required to pull the wood apart. (Enter your answers rounded to the nearest whole number.) low=…
Please answer the following: Thank you. A study was conducted on levels of PBC in soil samples in both rural and urban areas with the following results in PPM units: Rural: 3.5 1.0 1.6. 12.0 8.1 5.3 23.0 8.2 1.8 9.8 1.5 9.7 9.0 Urban: 24.0 11.0 107.0 18.0 29.0 49.0 94.0 12.0 16.0 22.0 141.0 18.0 21.0 13.0 11.0. Construct two boxplots, one for rural and one for urban. Write a paragraph comparing the two distributions.
In an experiment to determine whether there is asystematic difference between the weightsobtained with two different scales, 10 rockspecimens were weighed, in grams, on eachscale. The following data were obtained: Specimen weight scale 1 weight scale 2 1 11.23 11.27 2 14.36 14.41 3 8.33 8.35 4 10.50 10.52 5 23.42 23.41 6 9.15 9.17 7 13.47 13.52 8 6.47 6.46 9 12.40 12.45 10 19.38 19.35 Can you conclude that the mean weight differsbetween the scales? Use a 1% level ofsignificance. Assume that the weights arenormally…
STATE: How heavy a load (in pounds) is needed to pull apart pieces of Douglas fir 44 inches long and 1.51.5 inches square? Given are data from students doing a laboratory exercise. 33,190 31,860 32,590 26,520 33,280 32,320 33,020 32,030 30,460 32,700 23,040 30,930 32,720 33,650 32,340 24,050 30,170 31,300 28,730 31,920 To access the complete data set, click the link for your preferred software format: Excel Minitab JMP SPSS TI R Mac-TXT PC-TXT CSV CrunchIt! We are willing to regard the wood pieces prepared for the lab session as an SRS of all similar pieces of Douglas fir. Engineers also commonly assume that characteristics of materials vary Normally. Suppose that the strength of pieces of wood like these follows a Normal distribution with standard deviation 3000 pounds. PLAN: We will estimate ?μ by giving a 98% confidence interval. SOLVE: Find the sample mean ?¯ . (Enter your answer rounded to the nearest whole number.) ?¯= Give a 98% confidence…

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(b) Use rules of variance to obtaln an expression for the varlance and standard deviation (standard error) estimator In part (a). V(X - Y)- V(X) + V() -ox + oy? ax - y VV(X - Y)