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(b) What is the 95% confidence interval estimate of the population mean examination score if a sample of 100 applications provided a sample mean x = 833? A confidence interval for a population mean, u, is found by adding and subtracting the margin of error, E, to the given sample mean, as follows. Recall that z, is the standard normal random variable corresponding to a particular level of confidence and n is the sample size. x+ E, where E = z2 A sample of 100 applications provided a mean of 833 and the standard deviation is known to be 150. Thus, n = and . Now the value of za is needed. A 95% confidence interval is to be found. The margin of error corresponding to a 95% confidence level is needed, which is calculated using z2. Common values for z, for various confidence levels are given below. * Za/2 Confidence Level a 90% 0.10 0.05 1.645 95% 0.05 0.025 1.960 99% 0.01 0.005 2.576 For a 95% confidence level, the necessary value for z/2 is

(b) What is the 95% confidence interval estimate of the population mean examination score if a sample of 100 applications provided a sample mean x = 833? A confidence interval for a population mean, u, is found by adding and subtracting the margin of error, E, to the given sample mean, as follows. Recall that z, is the standard normal random variable corresponding to a particular level of confidence and n is the sample size. x+ E, where E = z2 A sample of 100 applications provided a mean of 833 and the standard deviation is known to be 150. Thus, n = and . Now the value of za is needed. A 95% confidence interval is to be found. The margin of error corresponding to a 95% confidence level is needed, which is calculated using z2. Common values for z, for various confidence levels are given below. * Za/2 Confidence Level a 90% 0.10 0.05 1.645 95% 0.05 0.025 1.960 99% 0.01 0.005 2.576 For a 95% confidence level, the necessary value for z/2 is

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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At a university the historical mean of scholarship examination scores for freshman applications is 800. A historical population standard deviation  ? = 150  is assumed known. Each year, the assistant dean uses a sample of applications to determine whether the mean examination score for the new freshman applications has changed.

 

 

(b) What is the 95% confidence interval estimate of the population mean examination score if a sample of 100 applications provided a sample mean x = 833? A confidence interval for a population mean, u, is found by adding and subtracting the margin of error, E, to the given sample mean, as follows. Recall that z, is the standard normal random variable corresponding to a particular level of confidence and n is the sample size. x+ E, where E = z A sample of 100 applications provided a mean of 833 and the standard deviation is known to be 150. Thus, n = and Now the value of za is needed. A 95% confidence interval is to be found. The margin of error corresponding to a 95% confidence level is needed, which is calculated using z2: Common values for z2 for various confidence levels are given below. Confidence Level Za/2 a 90% 0.10 0.05 1.645 95% 0.05 0.025 1.960 99% 0.01 0.005 2.576 For a 95% confidence level, the necessary value for z12 is
Transcribed Image Text:(b) What is the 95% confidence interval estimate of the population mean examination score if a sample of 100 applications provided a sample mean x = 833? A confidence interval for a population mean, u, is found by adding and subtracting the margin of error, E, to the given sample mean, as follows. Recall that z, is the standard normal random variable corresponding to a particular level of confidence and n is the sample size. x+ E, where E = z A sample of 100 applications provided a mean of 833 and the standard deviation is known to be 150. Thus, n = and Now the value of za is needed. A 95% confidence interval is to be found. The margin of error corresponding to a 95% confidence level is needed, which is calculated using z2: Common values for z2 for various confidence levels are given below. Confidence Level Za/2 a 90% 0.10 0.05 1.645 95% 0.05 0.025 1.960 99% 0.01 0.005 2.576 For a 95% confidence level, the necessary value for z12 is
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