b. 3.01 x 1023 atoms of Rubidium c. 8.08 x 1022 atoms of Krypton d. 2.997 x 1025 atoms of Vanadium

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Chapter8: Chemical Composition
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Problem 128CP: itamin B12 , cyancobalamin, is essential for human nutrition. Its molecular formula is...
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A. PROBLEM SOLVING
1. Calculate the amount in moles in each of the following quantities. The first one is done for you.
1 mol Pb
6.022 x 1023 atoms of Pb
5.7 x 10 ° atoms of Pb x
= 9 x 10 -15 mol Pb
%3D
a. 5.7 x 10° atoms of Lead
b. 3.01 x 1023 atoms of Rubidium
c. 8.08 x 1022 atoms of Krypton
d. 2.997 x 1025 atoms of Vanadium
2. Calculate the number of atoms in each of the following amounts.
2.5 mot Mg x 6.022 x 10 atoms Mg = 2 x 1024 atoms Mg
1 mol Mg
a. 1.004 mol bismuth
b. 32.6 mol strontium
Transcribed Image Text:A. PROBLEM SOLVING 1. Calculate the amount in moles in each of the following quantities. The first one is done for you. 1 mol Pb 6.022 x 1023 atoms of Pb 5.7 x 10 ° atoms of Pb x = 9 x 10 -15 mol Pb %3D a. 5.7 x 10° atoms of Lead b. 3.01 x 1023 atoms of Rubidium c. 8.08 x 1022 atoms of Krypton d. 2.997 x 1025 atoms of Vanadium 2. Calculate the number of atoms in each of the following amounts. 2.5 mot Mg x 6.022 x 10 atoms Mg = 2 x 1024 atoms Mg 1 mol Mg a. 1.004 mol bismuth b. 32.6 mol strontium
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