(b). A hole of 30 mm diameter and 75 mm depth is to be drilled. The suggested feed is 1.3 mm per rev and the cutting speed is 62 m/ min. assuming tool approach and tool overtravel as 6 mm, determine: i. spindle rpm ii. feed speed iii. cutting time iv. material removal rate

(b). A hole of 30 mm diameter and 75 mm depth is to be drilled. The suggested feed is 1.3 mm per rev and the cutting speed is 62 m/ min. assuming tool approach and tool overtravel as 6 mm, determine: i. spindle rpm ii. feed speed iii. cutting time iv. material removal rate

Precision Machining Technology (MindTap Course List)

2nd Edition

ISBN:9781285444543

Author:Peter J. Hoffman, Eric S. Hopewell, Brian Janes

Publisher:Peter J. Hoffman, Eric S. Hopewell, Brian Janes

Chapter5: Turning

Section5.3: Machining Operations On The Lathe

Problem 5RQ: Calculate spindle RPM and machining time for cutting a 1.5" diameter 4" long at 225 SFPM using a...

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operation, the shear IS cIose to, In turning operation, spindle speed is set to provide a cutting speed of 2.2 m/: The feed and depth of cut are 0.32 mm and 2.1 mm, respectively. The tool rake angle is 15°. After the cut, the deformed chip thickness is measured to be 0.43 mm. Using the Orthogonal model as an approximation of turning operation, the shear strain is close to, In turning operation, spindle speed is set to provide a cutting speed of 2.4 m/
Answer the following questions by circling True or False. 1. Capstan and turret lathes utilise many tools simultaneously to improve the productivity. ... 2. Lead screws in the machine tools can convert linear motion to rotary motion. 3. Automatic lathes are used for medium batch production. 4. Arithmetic progression is preferred for higher spindle speeds. 5. Tool layouts can be converted into a cam profile that is used for the control of the tool. () () 6. Higher the rake angle, less the cutting forces. 7. A very large clearance angle increases the strength of the tool tip. 8. The continuous chip causes poor surface finish and low tool life. 9. Ceramics are the hardest tool materials in the world. 10. The smaller the cutting ratio, the larger the cutting deformation. 11. A shaper can be used for maching flat surfaces in horizontal and angular directions. 12. During the return stroke of the shaper, the cutting tool will simply be sliding... 13. The cutting speed of the hydraulic shaper…
Turning Operation In a production turning operation, the foreman has decreed that a single pass must be completed on the cylindrical workpiece in 4.8 min. The piece is 400 mm long and 150 mm in diameter. Using a feed = 0.43 mm/rev and a depth of cut = 4.0 mm, what cutting speed must be used to meet this machining time requirement? Hint: Re-arrange the Tm equation to find v in m/min Tm= T.DO.L v.f 1.522
Standard time & work sampling The following data resulted from a time study made on a horizontal milling machine: Mean manual effort time per cycle: 4.62 min Mean cutting time (power feed): 3.74 min Mean performance rating: 115 percent Machine allowance (power feed): 10 percent Fatigue allowance: 15 percent questions: 1.) What is the Basic Time for the manual effort? 2.) What is the Standard Time for the manual effort? 3.) What is the Standard Time for the machine?
The following data were obtained in a study taken on a horizontal milling machine:Parts produced per cycle: 8.Average measured cycle time: 8.36 minutes.Average measured stress time per cycle: 4.62 minutes.Average fast traverse time: 0.08 minutes.Average cutting time with electrical power: 3.66 minutes.Performance rating: 115%.Clearance (machine time): 10%.Slack (effort time): 15%.The operator works on the task 8 hours a day and produces 380 parts. How many standard hours does the operator work? What is the operator's efficiency for the 8-hour day?
Answer the following questions by circling True or False. 5. Tool layouts can be converted into a cam profile that is used for the control of the tool. .... () 6. Higher the rake angle, less the cutting forces. 7. A very large clearance angle increases the strength of the tool tip. 8. The continuous chip causes poor surface finish and low tool life. 9. Ceramics are the hardest tool materials in the world. 10. The smaller the cutting ratio, the larger the cutting deformation. 11. A shaper can be used for maching flat surfaces in horizontal and angular directions. 12. During the return stroke of the shaper, the cutting tool will simply be sliding... 13. The cutting speed of the hydraulic shaper changes throughout most of the cutting stroke. 14. Arbour-mounted cutters are used in vertical axis machines to generate flat surfaces... 15. Dividing head is an important attachment that is used to divide the periphery of the workpiece into a number of divisions to machine surfaces.. () () ()
The following data were obtained in a study taken on a horizontal milling machine:Parts produced per cycle: 8.Average measured cycle time: 8.36 minutes. Average measured stress time per cycle: 4.62 minutes. Average fast traverse time: 0.08 minutes. Average cutting time with electrical power: 3.66 minutes. Performance rating: 115%. Clearance (machine time): 10%. Slack (effort time): 15%. The operator works on the task 8 hours a day and produces 380 parts. How many standard hours does the operator work? What is the operator's efficiency for the 8-hour day?
Q1:- Put a mark of True or false for below:- (a):- The milling cutting tool has a single cutting edge? (b):- At the break-even point, the total revenue equals the total cost? (c):- The right-hand rule is used to define machine axes? (d):- Design error is a simple mistake? (e):- The quality of products is poor in mass production? (f):- Allowances must be left before turning? (g):- Up-ward milling is better than down-ward milling?
Expert Q&A Done The top surface of a rectangular workpart is machined using a peripheral milling operation. The workpart is 735 mm long by 50 mm wide by 95 mm thick. The milling cutter, which is 60 mm in diameter and has five teeth, overhangs the width of the part equally on both sides. Cutting speed = 80 m/min, chip load = 0.30 mm/tooth, and depth of cut = 7.5 mm. (a) Determine the time required to make one pass across the surface, given that the setup and machine settings provide an approach distance of 5 mm before actual cutting begins and an overtravel distance of 25 mm after 1.2 9. 20 65 73 actual cutting has finished v in seconds. (b) What is the maximum material 3.9 239 removal rate during the cut v in mm3/sec? 0.127 5
QUESTION 5 Determine the spindle speed (rpm), the feed rate (in/min) and the cutting power required for turning a 1º diameter copper rod with a depth of cut of 0.1" using a cemented carbide tool. O N=287 RPM, F-25.8 in/min, P=9.7 hp ON=2866 RPM, F=258 in/min, P=97 hp ON=1146 RPM, F-25.8 in/min, P=97 hp O N= 11460 RPM, F-340 in/min, P=130 hp ON= 1146 RPM, F-34 inimin, P= 13 hp ON= 115 RPM, F-3.4 in/min, P=1.3 hp QUESTION 6 It is required to face mill an aluminum block to size it down from 2" to 1.5" thick using a 3" diameter 2-toothed carbide cutting tool. The block is 6.0" wide and 6" long. The entire tool diameter engages the workpiece during the cut. Calculate the recommended spindle speed in revolutions per minute, feed per tooth, and cutting power required. O N=1529 RPM, f= 0.026 in/rev/tooth, P = 36 hp O N-3820 RPM, f= 26 in/revitooth, P=27 hp O N-3820 RPM, f= 0.052 in/rew/tooth, P=27 hp ON-382 RPM, F= 0.026 in/revitooth, P = 0.027 hp O N-3820 RPM, f= 0.052 in/rev/tooth, P=2.7 hp…
3) Turning: A turning operation is to be adopted under the following machining conditions: Cutting speed: V = 75 m/min Feed rate: f= 0.25 mm/rev Depth of cut: a = 1.75 mm External workpiece diameter: Do = 50 mm Determine: a. The final workpiece diameter b. The rotational speed of the workpiece c. The tool feed rate expressed in m/min d. The material removal rate mm³/min e. The specific energy of the material assuming that the measured cutting force is F= 750 N. Knowing the specific energy, which of materials from the table below could the workpiece be composed? Approximate Specific-Energy Requirements in Cutting Operations SPECIFIC ENERGY* MATERIAL Aluminum alloys Cast irons Copper alloys High-temperature alloys W-s/mm³ 0.4-1.1 1.6-5.5 1.4-3.3 3.3-8.5 0.4-0.6 4.9-6.8 3.8-9.6 3.0-5.2 2.7-9.3 3.0-4.1 hp-min/in³ 0.15-0.4 0.6-2.0 0.5-1.2 1.2-3.1 0.15-0.2 1.8-2.5 1.1-3.5 1.1-1.9 1.0-3.4 1.1-1.5 Magnesium alloys Nickel alloys Refractory alloys Stainless steels Steels Titanium alloys * At…
14. Determine the proper RPM for a 3" piece of cold-rolled steel with a cutting speed of SFPM. Round the nearest RPM. Hint: Refer to formulas and examples in your textb а. 102 b. 115 C. 87 d. 146 15. Calculate the machining time (in minutes, rounded to the nearest minute) for a part in length 10" diameter AISI/SAE 4140 steel using a cutting speed of 110 SFPM and a rate of 0.008 IPR. Hint: Refer to examples in your textbook. а. 47 b. 60 C. 86 d. 74