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- ) Which of the following compounds will be most soluble in ethanol (CH3CH2OH)? A) ethylene glycol (HOCH2CH2OH) B) hexane (CH3CH2CH2CH2CH2CH3) C) acetone (CH3COCH3)D) trimethylamine (N(CH3)3) E) A and D are soluble in ethanol.Two diastereomeric sets of enantiomers, A/B and C/D, exist for 3-bromo-2-butanol. When enantiomer A or B is treated with HBr, only racemic 2,3-dibromobutane is formed; no meso isomer is formed. When enantiomer C or D is treated with HBr, only meso 2,3-dibromobutane is formed; no racemic 2,3-dibromobutane is formed. Account for these observations.8.1)The enol content of CH3COCH2CO2Et in hexane is 46% and that in water is 0.4%. Thereason for the above observation is as follows: (A) Intermolecular hydrogen bonding is stabilized by hexane. (B) Intramolecular hydrogen bonding is stabilized by water. (C) Intramolecular hydrogen bonding is destabilized by water. (D) CH3COCH2CO2Et dissolves in hexane completely. 2)The molecular formula of glucose is C6H12O6. The chemical composition of glucose is(A) 39.99 % C, 6.71 % H, 53.27 % O (B) 40.99 % C, 6.71 % H, 53.27 % O(C) 39.99 % C, 7.71 % H, 54.27 % O (D) 29.99 % C, 7.71 % H, 53.00 % O 3)20 mL of 0.2 M hydrochloric acid is added to 5 mL of 0.1 M sodium carbonate. Theresultant solution is then titrated against 0.2 M sodium hydroxide. What will be the titrevalue?(A) 15 mL (B) 10 mL (C) 5 mL (D) 20 mL 4) High thermal stabilities of transition metal carbonyls are due to- (A) non-availability of d-orbital on carbon. (B) formation of an ionic bond between CO and metal. (C) interaction of…
- Which member of each pair is more soluble in water? Why?(a) CH₃CH₂OCH₂CH₃(l) or CH₃CH₂OCH₃(g)(b) CH₂Cl₂(l) or CCl₄(l)Aspartame, the sweetener used in the commercial products NutraSweet and Equal, is 200 times sweeter than sucrose. What products will be obtained ifaspartame is hydrolyzed completely in an aqueous solution of HCl?1. Optical isomers differ in:a. sign of their optical activityb. their structurec. sign and magnitude of their optical activityd. magnitude of their optical activitye. All of the above 2. Which compound contains an asymmetric carbon?a. n-butanol d. 2-methyl-1-butanolb. Isopropyl alcohol e. None of the abovec. 1-bromo-2-methyl-1-propene 3. Which of the compounds can exist as enantiomers?A. Isopropyl chlorideB. BromochloromethaneC. Sec-butyl chlorideD. 1-chloro-2methylpentane a. A and B b. B and D c. C and D d. B and C
- 4-Methylphenol, CH3C6H4OH (pKa 10.26), is only slightly soluble in water, but its sodium salt, CH3C6H4O- Na+, is quite soluble in water. In which solution(s) will 4-methylphenol dissolve? Q.) Aqueous Na2CO3Would you expect hemiacetals to be stable in basic solutions? Explain your answer.Rank the following groups in order of decreasing priority (1 = highest, 4 = lowest)
- 4-Methylphenol, CH3C6H4OH (pKa 10.26), is only slightly soluble in water, but its sodium salt, CH3C6H4O- Na+, is quite soluble in water. In which solution(s) will 4-methylphenol dissolve? Q.) Aqueous NaOHUnknown Results - Solubility Test: - Slightly soluble Ceric Ammounium Nitrate Test: - Positive Iron (III) Chloride Test: - Negative Chromic Acid Test: - Positive Iodoform Test: - Negative Luca's Test: - Negative The known alcohols tested in this experiment are: Ethanol 1-Propanol 2-Propanol 1-Butanol 2-Pentanol 2-Methyl-2-propanol 1-Octanol Phenol Although you didn't carry out every test on all eight alcohols, you should be able to predict the results for the tests on the alcohols that you did not test. If your unknown alcohol is one of these eight known alcohols, which do you think yours is? Can you definitely identify it? Explain your answer using your test results and predicted results.Explain the order of boiling points of the isomeric alcohols but an_1_ol boiling point of 118°C,but an_2_al boiling point of 99°C and 2_methylpropan_2_al boiling point 82°C Menthone and menthal are both isolated from mint ,explain why menthal is a solid at room temperature while menthone is a liquid at room temperature The boiling point of cis _but_2_ene is 3.7°C whereas that of trans_but_2_ene is 0.9°C explain