balanced three-phase system with a line voltage of 300 V is supplying a balanced Y-connected load with 1200 W at a A. Round off to two(2) decimal places, do not write units. The magnitude of the line current is The per-phase load impedance is Ohms. No decimal places, do not write units. The angle of the impedance is Degrees Round off to one(1) decimal place, do not write units

balanced three-phase system with a line voltage of 300 V is supplying a balanced Y-connected load with 1200 W at a A. Round off to two(2) decimal places, do not write units. The magnitude of the line current is The per-phase load impedance is Ohms. No decimal places, do not write units. The angle of the impedance is Degrees Round off to one(1) decimal place, do not write units

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter2: Fundamentals

Section: Chapter Questions

Problem 2.40P: A balanced three-phase 240-V source supplies a balanced three-phase Load. If the line current IA is...

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A balanced three-phase load is connected to a 4.16-kV, three-phase, fourwire, grounded-wye dedicated distribution feeder. The load can be mode led by an impedance of ZL=(4.7+j9)/phase, wye-connected. The impedance of the phase conductors is (0.3+j1). Determine the following by using the phase A to neutral voltage as a reference and assume positive phase sequence: (a) Line currents for phases A, B, and C. (b) Line-to-neutral voltages for all three phases at the load. (c) Apparent. active, and reactive power dissipated per phase, and for all three phases in the load. (d) Active power losses per phase and for all three phases in the phase conductors.
Two balanced three-phase loads that are connected in parallel are fed by a three-phase line having a series impedance of (0.4j2.7) per phase. One of the loads absorbs 560 kVA at 0.707 power factor lagging, and the other 132 kW at unity power factor. The line-to-line voltage at the load end of the line is 2203V. Compute (a) the line-to-line voltage at the source end of the line. (b) the total real and reactive power losses in the three-phase line, and (c) the total three-phase real and reactive power supplied at the sending end of the line. Check that the total three-phase complex power delivered by the source equals the total three-phase comp lex power absorbed by the line and loads.
A three-phase line, which has an impedance of (2+j4) per phase, feeds two balanced three-phase loads that are connected in parallel. One of the loads is Y-connected with an impedance of (30+j40) per phase, and the other is -connected with an impedance of (60j45) per phase. The line is energized at the sending end from a 60-Hz, three-phase, balanced voltage source of 1203V (rms. line-to-line). Determine (a) the current, real power. and reactive power delivered by the sending-end source: (b) the line-to-line voltage at the load: (C) the current per phase in each load: and (d) the total three-phase real and reactive powers absorbed by each load and by the line. Check that the total three- phase complex power delivered by the source equals the total three-phase power absorbed by the line and loads.
A balanced three-phase 240-V source supplies a balanced three-phase Load. If the line current IA is measured to be 15 A and is in phase with the line-to-line voltage, VBC, find the per-phase load impedance if the load is (a) Y-connected, (b) -conneeted.
Figure 2.33 gives the general -Y transformation. (a) Show that the general transformation reduces to that given in Figure 2.16 for a balanced three-phase load. (b) Determine the impedances of the equivalent Y for the following impedances: ZAB=j10,ZBC=j20, and ZCA=j25. ZAB=ZAZB+ZBAC+ZCZAZCZA=ZABZCAZAB+ZBC+ZCAZBC=ZAZB+ZBAC+ZCZAZAZB=ZABZBCZAB+ZBC+ZCAZCA=ZAZB+ZBAC+ZCZAZBZA=ZCAZBCZAB+ZBC+ZCA
A Y-connected load bank with a three-phase rating of 500 kVA and 2300 V consists of three identical resistors of 10.58. The load bank has the following applied voltages: Vab=184082.8,Vbc=276041.4, and Vca=2300180V. Determine the symmetrical components of (a) the line-to-line voltages Vab0,Vab1, and Vab2, (b) the line-to-neutral voltages and Van0,Van1, and Van2, (c) and the line currents Ia0,Ia1, and Ia2. (Note that the absence of a neutral connection means that zero-sequence currents are not present.)
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It is stated that (i) balanced three-phase circuits can be solved in per unit on a per-phase basis after converting - load impedances to equivalent Y impedances. (ii) Base values can be selected either on a per-phase basis or on a three-phase basis. (a) Both statements are true. (b) Neither is true. (c) Only one of the above is true.
For Figure 1: A short 3-phase line with an impedance of (6+j8) per line has sending end and receiving end line voltages of 120 and 110 kV, respectively. If the power factor at this loading is 0.90 lagging, determine (a) the current delivered to the load, (b) the power consumed by the balanced 3-phase load in kW, and (c) the voltage regulation of the system. (hint: Voltage at the sending and receiving have some magnitude but different angles.)
Consider the configuration from Problem 1, except that each phase of the transmission line has an impedance of ݆1.5 Ω. a. Determine the line currents. b. Determine the line‐neutral voltage for each branch of the 3Φ load. c. Determine the complex power consumed by the 3Φ load. d. Determine the complex power produced by the 3Φ source. e. Determine the power consumed by the transmission line. f. Determine the load power factor, and the power factor observed by the source. problem 1 : Each leg of a symmetric, Y‐connected, 3Φ load has an impedance of 10∠36.87° Ω, and is connected to A 60 Hz, balanced, positive‐sequence, Y‐connected 3Φ voltage source with Vrms .3Φ source via an ideal transmission line (that is, the connection from the source to the load has zero impedance).
1. A 69-kV, three-phase short transmission line is 16 km long. The line has a per phase series impedance of 0.125+j0.4375 Ω per km. Determine the sending end voltage, voltage regulation, the sending end power, and the transmission efficiency when the line delivers (a) 70 MVA, 0.8 lagging power factor at 64 kV. (b) 120 MW, unity power factor at 64 kV. Use lineperf program to verify your results. 2. A three-phase, 765-kV, 60-Hz transposed line is composed of four ACSR, l,431,000-cmil, 45/7 Bobolink conductors per phase with flat horizontal spacing of 14 m. The conductors have a diameter of 3.625 cm and a GMR of 1.439 cm. The bundle spacing is 45 cm. The line is 400 km long, and for the purpose of this problem, a lossless line is assumed. (a) Determine the transmission line surge impedance Zc, phase constant ß, Wavelength, the surge impedance loading SIL, and the ABCD constant. b) The line delivers 2000 MVA at 0.8 lagging power factor at 735 kV. Determine the sending end quantities and…
Question-2) The parameters of a three-phase transmission line are given as Z = (12.84 + j72, 76)Ω and y = j5, 83x10^-4 mho. At the end of the line, a power of 55 MVA with a power factor of 0.8 is drawn under 132 kV voltage. Accordingly, calculate the line head voltage, active and reactive power values per line, and voltage regulation of the line using the nominal π circuit.7-) Since 55 MVA power is drawn from the end of the line under the conditions mentioned above, calculate the line head voltage (phase-phase voltage) and enter it in the box below. (The value will be entered in kiloVolts. Only the amplitude value of the voltage will be entered. The phase value will NOT be entered!!! Two digits after the comma will be sufficient. )8-) Since 55 MVA power is drawn from the end of the line under the conditions mentioned above, calculate the active power value per line and enter it in the box below. (The value will be entered in MegaWatt. It will be sufficient to take two digits after…