
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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Base on the coding strand of DNA: ATG GGA ATT CGC What is the sequence of the complementary template strand of DNA that pairs with the coding strand?
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- Produce the RNA strand that would be read from the DNA strand T -- A C -- G C -- G A -- A -- C -- G -- T -- T-- A -- ف في نarrow_forwardThe type of DNA replication error illustrated in the diagram below is _______________________.arrow_forwardDNA STRAND IS 3’ TAC-AGC-ACT-CAG-TCA 5’, whats the non-template/sense/coding strand from the STARND DNA? also what's the arrangement of m-RNA and the chain arrangement of the amino acids that will be made according to the order of the RNA?PLS DONT ANSWER THE DEFINITION ONLY, READ THE QUESTION CAREFULLYarrow_forward
- Origin of replication [ Choose ] [Choose] Codon Complementary pairs with cytosine in a DNA molecule The site of protein synthesis Ribozyme This molecule can begin the synthesis of a polymer of nucleotides without a primer A short peice of lagging stand DNA Primase A reflection of redundancy in the genetic code RNA which exhibits enzymatic properties Okazaki Fragment The process of making RNA from DNA Helicase DNA polymerase Transcription Enzyme which lays down a segment of RNA on replicating DNA so that DNA nucleotides can polymerize A sequence of three nucletotides which codes for an amino acid Ribosome Point Mutation Chromosome Wobble Position The point on a stand of DNA where replication begins Mitochondria RNA polymerase [ Choose ] Guaninearrow_forwardDraw out the molecular structure of a double stranded DNA molecule. This molecule is 6 bp in size. Don't forget label.arrow_forwardGive 3 strand slippage and trinucleotide repeat disorder examplesarrow_forward
- Give the DNA compliment to the following DNA strand. ATG UAC b. TAC GTG OMGarrow_forwardMatch the enzyme on the left with its role in DNA replication DNA polymerase I helicase DNA ligase DNA polymerase III topoisomerase primase 72 W w# 3 E $ 4 R % 5 T A 6 MacBook Pro Y & 7 U * 8 replaces primers with DNA connects Okazaki fragments to form a continuous strand of DNA synthesizes short RNA fragments used to initiate DNA synthesis Uses the 3'OH of an RNA primer to synthesize the leading strand and Okazaki fragments keeps DNA from getting tangled up ahead of the replication fork "unwinds" the DNA double helix at the origin and replication forks 1 ( 9 X 0 0 P + 11 Nextarrow_forwardDetermine the complementary DNA strand that would form. Next, write the mRNA that would form from each complementary DNA strand you created (normal and mutated). Remember that adenine in DNA matches with uracil in RNA, thymine in DNA matches with adenine in RNA, and guanine and cytosine go together. Normal DNA strand - CTG ACT CCT GAG GAG Mutated DNA strand - CTG ACT CCT GTG GAGarrow_forward
- Complete the complementary stand of the DNA shown Complementary strand стАG GTACT CAC Garrow_forwardIf DNA segments changes from GCATAG to GCATA, this is a: MRNA Codon/Amino Acid Chart First Base Second Base Third Base U A G 0001 Phenylalanine UCU UAU1 Tyrosine (Tyr) UAC UGUT FCcysteine (Cys) UGCJ U UUCJ (Phe) UCC Serine (Ser) UCA U UUA1 UAAT UGA - Stop A FLeucine (Leu) UUG- FStop UAG- UCG- UGG - Tryptophan (Trp) G CU- CCU CGUT CAU1 Histidine (His) CAC U CUC FLeucine (Leu) CUA CC Proline (Pro) CCA CGC FArginine (Arg) CGA CAA1 Glutamine A CAGI (Glu) CGG- CUG- CCG- G AUU AAU1 Asparagine ACU1 AGUT FSerine (Ser) AGC- AUC FIsoleucine (le) ACC Threonir AACJ (Asn) A AUA- ACA (Thr) AAA1 FLysine (Lys) AAG- AGA, FArginine (Arg) AGG- A Start Methionine (Met) ACG- AUG - GUU- GCU GAU- GGU | Aspartic Acid GAÇJ(Asp) U GỤC Valine (Val) GUA GCC FAlanine (Ala) GGC Glycine (Gly) GGA G GAA1 Glutamic Acid A GCA GCG- GAGJ (Glu) GGG- GUG- Garrow_forward5'-GCGGTACGTTACGGCTTTACTGACCTGCAGGC-3' A. Convert this to a double strand DNA molecule by writing the complementary sequence. Be sure to correctly label the ends of the double stranded molecule B. Pick one of the two strands and write the sequence of an RNA molecule that could be transcribed from it. Again, you must correctly label the ends of the molecule.arrow_forward
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