Based in the table 1. (need to answer question 4,5,6) 1) Develop a best-fit equation for the relationship between stress and strain. Employ Naïve–Gauss elimination method whenever necessary. S=___28.65___+___294.43___e + ___235.22____e2 2) Determine the coefficient of determination for the equation. R2 =___0.636____ 3) Calculate the stress value to the most accurate value at strain value 0.53. s = ___250.76____Pa 4) The yield point is the point on a stress–strain curve that indicates the limit of elastic behaviour and the beginning of plastic behavior. In this case, the yield point occurs at a stress value of 80. Determine the corresponding strain value at the yield point. In any relevant method, use a stopping criterion of 0.05% e =_______ 5) The ultimate strength is the maximum point on the stress–strain curve. This corresponds to the maximum stress that can be sustained by a structure in tension. Compute the ultimate strength point of the polymeric material (strain value that gives maximum stress). In any relevant method, use a stopping criterion of 0.05%. e =______  and smax =______Pa 6) Determine the absolute error between the highest experimental data and the calculated maximum concentration. Error =_____%

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
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Based in the table 1. (need to answer question 4,5,6)
1) Develop a best-fit equation for the relationship between stress and strain. Employ Naïve–Gauss elimination method whenever necessary.
S=___28.65___+___294.43___e + ___235.22____e2

2) Determine the coefficient of determination for the equation.

R2 =___0.636____

3) Calculate the stress value to the most accurate value at strain value 0.53.
s = ___250.76____Pa

4) The yield point is the point on a stress–strain curve that indicates the limit of elastic behaviour and the beginning of plastic behavior. In this case, the yield point occurs at a stress value of 80. Determine the corresponding strain value at the yield point. In any relevant method, use a stopping criterion of 0.05%

e =_______

5) The ultimate strength is the maximum point on the stress–strain curve. This corresponds to the maximum stress that can be sustained by a structure in tension. Compute the ultimate strength point of the polymeric material (strain value that gives maximum stress). In any relevant method, use a stopping criterion of 0.05%.

e =______  and smax =______Pa

6) Determine the absolute error between the highest experimental data and the calculated maximum concentration.

Error =_____%

 

Table 1 shows the stress-strain data for a new polymeric material rod subjected to an axial
load. The last point is observed as the rupture point.
Table 1: Stress-strain data for new polymeric material
Strain, e
Stress, s (Pa)
(dimensionless)
32
0.1
59
0.2
75
0.3
86
0.4
104
0.5
120
0.6
129
0.7
125
0.8
114
0.9
97
Transcribed Image Text:Table 1 shows the stress-strain data for a new polymeric material rod subjected to an axial load. The last point is observed as the rupture point. Table 1: Stress-strain data for new polymeric material Strain, e Stress, s (Pa) (dimensionless) 32 0.1 59 0.2 75 0.3 86 0.4 104 0.5 120 0.6 129 0.7 125 0.8 114 0.9 97
e
e2
e 3
e4
e.s
e2 s
32
0.1
59
0.1
0.001
0.0001
5.9
0.59
0.2
75
0.04
0.008
0.0016
1.5
3
0.3
86
0.09
0.027
0.0081
25.8
7.74
0.4
104
0.16
0.064
0.0256
41.6
16.64
0.5
120
0.25
0.125
0.0625
60
30
0.6
129
0.36
0.216
0.1296
77.4
46.44
0.7
125
0.49
0.343
0.2401
87.5
61.25
0.8
114
0.64
0.512
0.4096
91.2
72.96
0.9
97
0.81
0.729
0.6561
87.3
78.57
4.5
941
2.85
2.025
1.5333
491.7
317.19
Transcribed Image Text:e e2 e 3 e4 e.s e2 s 32 0.1 59 0.1 0.001 0.0001 5.9 0.59 0.2 75 0.04 0.008 0.0016 1.5 3 0.3 86 0.09 0.027 0.0081 25.8 7.74 0.4 104 0.16 0.064 0.0256 41.6 16.64 0.5 120 0.25 0.125 0.0625 60 30 0.6 129 0.36 0.216 0.1296 77.4 46.44 0.7 125 0.49 0.343 0.2401 87.5 61.25 0.8 114 0.64 0.512 0.4096 91.2 72.96 0.9 97 0.81 0.729 0.6561 87.3 78.57 4.5 941 2.85 2.025 1.5333 491.7 317.19
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