Based on a sample of n=28,the least-squares method was used to develop the prediction line Yi=8+4Xi. In addition, SYX=2.8, X=10, and ∑i=1nXi−X2=28. Complete parts (a) through (c) below. Question content area bottom Part 1 a. Construct a 90% confidence interval estimate of the population mean response for X=2. ≤μY|X=2≤ = (Round to two decimal places as needed.) Part 2 b. Construct a 90% prediction interval of an individual response for X=2. ≤YX=2≤ = (Round to two decimal places as needed.) Part 3 c. Compare the results of (a) and (b) with those forX=10, which are 47.10≤μY|X=10≤48.90 and 43.14≤YX=10≤52.86. Which intervals are wider? Why? The intervals for X= ▼ 22 1010 are wider because X=10 is ▼ different from equal OR equal to The mean X.
Based on a sample of n=28,the least-squares method was used to develop the prediction line Yi=8+4Xi. In addition, SYX=2.8, X=10, and ∑i=1nXi−X2=28. Complete parts (a) through (c) below. Question content area bottom Part 1 a. Construct a 90% confidence interval estimate of the population mean response for X=2. ≤μY|X=2≤ = (Round to two decimal places as needed.) Part 2 b. Construct a 90% prediction interval of an individual response for X=2. ≤YX=2≤ = (Round to two decimal places as needed.) Part 3 c. Compare the results of (a) and (b) with those forX=10, which are 47.10≤μY|X=10≤48.90 and 43.14≤YX=10≤52.86. Which intervals are wider? Why? The intervals for X= ▼ 22 1010 are wider because X=10 is ▼ different from equal OR equal to The mean X.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Based on a sample of n=28,the least-squares method was used to develop the prediction line Yi=8+4Xi. In addition, SYX=2.8, X=10, and ∑i=1nXi−X2=28.
Complete parts (a) through (c) below.
Complete parts (a) through (c) below.
Question content area bottom
Part 1
a. Construct a 90% confidence interval estimate of the population mean response for X=2.
≤μY|X=2≤ =
(Round to two decimal places as needed.)
Part 2
b. Construct a 90% prediction interval of an individual response for
X=2.
≤YX=2≤ =
(Round to two decimal places as needed.)
Part 3
c. Compare the results of (a) and (b) with those forX=10, which are 47.10≤μY|X=10≤48.90 and 43.14≤YX=10≤52.86.
Which intervals are wider? Why?
Which intervals are wider? Why?
The intervals for X= ▼ 22 1010 are wider because X=10 is
▼
different from equal OR equal to The mean X.Expert Solution
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