Based on the following wild type DNA sequence, indicate if each of the mutations should be classified as : insertion, deletion, missense, nonsense, silent (Use the provided Genetic Code table and remember you have been given DNA sequence). Wild Type: 5' ATG GCT AGA GTC GAG TTG 3' Mutant 1: 5' ATG GCA GAG TCG AGT TG 3' Mutant 2: 5' ATG GCT TGA GTC GAG TTG 3' Mutant 3: 5' ATG GCT AGA GTT GAG TTG 3' Mutant 4: 5' ATG GCT AGA AGT CGA GTT G 3' Mutant 5: 5' ATG GCT AGA ATC GAG GTT 3'

Based on the following wild type DNA sequence, indicate if each of the mutations should be classified as : insertion, deletion, missense, nonsense, silent (Use the provided Genetic Code table and remember you have been given DNA sequence). Wild Type: 5' ATG GCT AGA GTC GAG TTG 3' Mutant 1: 5' ATG GCA GAG TCG AGT TG 3' Mutant 2: 5' ATG GCT TGA GTC GAG TTG 3' Mutant 3: 5' ATG GCT AGA GTT GAG TTG 3' Mutant 4: 5' ATG GCT AGA AGT CGA GTT G 3' Mutant 5: 5' ATG GCT AGA ATC GAG GTT 3'

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter13: An Introduction To Genetic Technology

Section: Chapter Questions

Problem 20QP: Analyzing Cloned Sequences A base change (A to T) is the mutational event that created the mutant...

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Based on the following wild type DNA sequence, indicate if each of the mutations should be classified as : insertion, deletion, missense, nonsense, silent (Use the provided Genetic Code table and remember you have been given DNA sequence). Wild Type:      5’ ATG GCT AGA GTC GAG TTG 3’ Mutant 1:         5’ ATG GCA GAG TCG AGT TG 3’ Mutant 2:         5’ ATG GCT TGA GTC GAG TTG 3’ Mutant 3:         5’ ATG GCT AGA GTT GAG TTG 3’ Mutant 4:         5’ ATG GCT AGA AGT CGA GTT G 3’ Mutant 5:         5’ ATG GCT AGA ATC GAG GTT 3’
Based on the following wild type sequence, indicate if each of the mutations should be classified as : insertion, deletion, missense, nonsense, silent (Use the provided Genetic Code table). Wild Type: GUC GCC GAC GAG AGG Mutant 1:   GUC GCC AGA CGA GAG G Mutant 2:   GUC GCC ACG AGA GG Mutant 3:   GUC GCC AAC GAG AGG Mutant 4:   GUA GCC GAC GAG AGG Mutant 5:   GUC GCC GAC UAG AGG
Identify the following mutations and describe what the possible effect on the protein will be. (4) 5’GAT TTT AGC TTA GCC CAT 3’ 5’ GAT TAG CTT AGC CCA T 3’ 3’CTA AAA TCG AAT CGG GTA 5’                   3’ CTA ATC GAA TCG GGT A 5’ 5’ GAT TTT AGC TTA CCC CAT 3’                 5’ GAT TTT AGC TAA CCC CAT   3’ 3’ CTA AAA TCG AAT GGG GTA 5’                3’ CTA AAA TCG ATT GGG GTA 5’
The DNA sequence of one strand of a gene from threeindependently isolated mutants is given here (5′ endsare at left). Using this information, what is the sequence of the wild-type gene in this region?mutant 1 ACCGTAATCGACTGGTAAACTTTGCGCGmutant 2 ACCGTAGTCGACCGGTAAACTTTGCGCGmutant 3 ACCGTAGTCGACTGGTTAACTTTGCGCG
The most common MCAD mutation is shown below. The coding strand is shown for both the WT and mutant. The TATA box and kozak sequences are in parenthesis. What type of mutation is present? Wild-type:5’-ATGGCC[TATAT]ATGTCACTTGACTACGCAGCC[GCCACCATGG]ATATAGATAATGCGCGCATAGCATACTGAGGGTAGTAG-3’ Mutant:5’-ATGGCC[TATAT]ATGTCACTTGACTACGCAGCC[GCCACCATGG]ATATAGATAATGCGCGC AGAGCATACTGAGGGTAGTAG-3’ Answer: Is this a transition mutation? because there is an exchange of G instead of A? It kind of confuses me a little. help
The following sequence represents the dsDNA code for a short peptide 5' -CTT TCC CAT CAC CGC ATG CAT CCT CCC TCC TTT CTT TAA TAT TGG-3' 3'-GAA AGG GTA GTG GCG TAC GTA GGA GGG ACC AAA GAA ATT ATA ACC-5' Transcribe the DNA strand given above to write the sequence of the mRNA strand in the 5’ to 3’ direction. (1) Use the table and write the sequence of the resulting peptide. (1) Is it possible for a codon to code for another amino acid? (1) What will be the effect if a mutation changes the codon UAU to UAA? (1) What is a reading frame? (1) If you are given a nucleotide sequence, how would you find Open Reading Frames? (1) DISCUSS the reason why there are leading and lagging strands in replication?
For the given mutation below,please write down the reverse mutation and any intragenic suppressor mutations for that mutation. Use the codon table for amino acids as reference. In this case, mutation means single letter change. Mutation: AGA -> AGC Arg codons: CGU, CGC, CGA, CGG,AGA,ACG Ser codons: UCU, UCC, UCA, UCG, AGU, AGC Character limit is 10 characters. Write down Reverse mutation sequence first and then intragenic suppressor mutation sequence. Write down the mutated sequence not the mutation.
The following are DNA fragments containing a small gene. The top strand is the coding strand. Transcribe all groups and translate. FIND THE POSSIBLE MUTATIONS Group B - MUTATION 5’-GGCAATGGGTTTGTGAAATTCTAAAAGTTTTTAATTC-3’ 3’-CCGTTACCCAAACACTTTAAGATTTTCAAAAATTAAG-5’ Group C- 5’-GGCAATGGGTTTGTGCAATTCTAAGAGTTTTTAATTC-3’ 3’-CCGTTACCCAAACACGTTAAGATTCTCAAAAATTAAG-5’
The following are DNA fragments containing a small gene. The top strand is the coding strand. Transcribe all groups and translate. FIND THE POSSIBLE MUTATIONS Group D 5’-GGCAATGGGTTTGTGCAATTCTAACAGTTTTTAATTC-3’ 3’-CCGTTACCCAAACACGTTAAGATTGTCAAAAATTAAG-5’ Group E 5’-GGCAATGGGTTTTGCAATTCTAAAAGTTTTTAATTC-3’ 3’-CCGTTACCCAAAACGTTAAGATTTTCAAAAATTAAG
Which of the following set(s) of primers a–d couldyou use to amplify the following target DNA sequence, which is part of the last protein-coding exonof the CFTR gene?5′ GGCTAAGATCTGAATTTTCCGAG ... TTGGGCAATAATGTAGCGCCTT 3′3′ CCGATTCTAGACTTAAAAGGCTC ... AACCCGTTATTACATCGCGGAA 5′a. 5′ GGAAAATTCAGATCTTAG 3′;5′ TGGGCAATAATGTAGCGC 3′b. 5′ GCTAAGATCTGAATTTTC 3′;3′ ACCCGTTATTACATCGCG 5′c. 3′ GATTCTAGACTTAAAGGC 5′;3′ ACCCGTTATTACATCGCG 5′d. 5′ GCTAAGATCTGAATTTTC 3′;5′ TGGGCAATAATGTAGCGC 3′
Consider this sequence below: GAG TAC ACG AGT GGA Which of the following options is an example of a non-synonymous point mutation? (remember to translate to mRNA!) A. GAG TAC AAT CGA GTG GA B. GAG TAC ACG GGT GGA C. GAG TAC A–G AGT GGA D. GAG TAC ACG AGA GGA
The wildtype sequence of a gene is the following: wt: 3' TAC AAA TCT AGC CCG 5' and the following 3 mutations were found:, indicate what type of mutation this is 1: 3' TAC AAA TCA AGC CCG 5' ; 2. 3' TAC AAA TCT ATC CCG 5'. ; 3. 3' TAC AAA AGC CCG 5'. ;