Based on the result of the Chi-square test, does the observed number of kanamycin resistant colonies per plate follow a Poison distribution?  1. The analysis did not shown whether there might be a significant difference between the expectations of a Poison distribution and the number of colonies per kanamycin plate that we observed 2. The analysis has shown that there is a significant difference between the expectations of a Poison distribution and the number of colonies per kanamycin plate that we observed 3. The analysis has shown that there is not a significant difference between the expectations of a Poison distribution and the number of colonies per kanamycin plate that we observed 4. The analysis has shown that there might be a significant difference between the expectations of a Poison distribution and the number of colonies per kanamycin plate that we observed

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Based on the result of the Chi-square test, does the observed number of kanamycin resistant colonies per plate follow a Poison distribution? 

1. The analysis did not shown whether there might be a significant difference between the expectations of a Poison distribution and the number of colonies per kanamycin plate that we observed

2. The analysis has shown that there is a significant difference between the expectations of a Poison distribution and the number of colonies per kanamycin plate that we observed

3. The analysis has shown that there is not a significant difference between the expectations of a Poison distribution and the number of colonies per kanamycin plate that we observed

4. The analysis has shown that there might be a significant difference between the expectations of a Poison distribution and the number of colonies per kanamycin plate that we observed

 

We transformed E coli cells with a plasmid modified to contain a 'virulence factor' which would allow growth on media containing the antibiotic kanamycin (Kan). The plasmid confers constitutive
resistance to ampicillin (Amp). The bacterial experiment is about understanding whether such a 'virulence factor' confers physiological adaptation to Kan or whether the development of resistance can
be explained by random mutations.
For each independent transformation we re-suspended the cells from three colonies in Luria broth. For each suspension of cells we plated 100 microliters on a Kan plate. To estimate the number of
cells seeded on each Kan plate we made serial dilutions that were plated on Amp plates and we counted the number of cells growing on them. From this we extrapolated how many cells had been
seeded on the Kan plate. Then we normalised the Kan results for all the plates, assuming that every plate had been seeded with 10[5] cells. The table below shows the results.
Normalised
number of
colonies per
Kan plate
012345CI2S8G
7
11
16
60
79
Observed
N of
plates
151
20
13
7
2
1
1
2
0
3
0
1
1
Transcribed Image Text:We transformed E coli cells with a plasmid modified to contain a 'virulence factor' which would allow growth on media containing the antibiotic kanamycin (Kan). The plasmid confers constitutive resistance to ampicillin (Amp). The bacterial experiment is about understanding whether such a 'virulence factor' confers physiological adaptation to Kan or whether the development of resistance can be explained by random mutations. For each independent transformation we re-suspended the cells from three colonies in Luria broth. For each suspension of cells we plated 100 microliters on a Kan plate. To estimate the number of cells seeded on each Kan plate we made serial dilutions that were plated on Amp plates and we counted the number of cells growing on them. From this we extrapolated how many cells had been seeded on the Kan plate. Then we normalised the Kan results for all the plates, assuming that every plate had been seeded with 10[5] cells. The table below shows the results. Normalised number of colonies per Kan plate 012345CI2S8G 7 11 16 60 79 Observed N of plates 151 20 13 7 2 1 1 2 0 3 0 1 1
Normalised
number of
colonies per
Kan plate
0
5678AWNIO
1
2
4
9
10
11
12
16
60
79
83
Observed
N of
plates
151
20
13
7
. ܝ ܝ ܝ ܚ ܘ ܚ ܘ ܝ . . . .
2
2
0
1
1
Using these observed numbers and assuming a Poisson distribution we have calculated the expected number of plates for each category (each row of the table above is a category). We have used the
Chi-square statistic to test whether the observed number of plates per category are in agreement with the Poisson distribution. Note that to respect the mathematical assumptions of the Chi-square,
we have combined into one all categories with 6 or more colonies per plate.
Transcribed Image Text:Normalised number of colonies per Kan plate 0 5678AWNIO 1 2 4 9 10 11 12 16 60 79 83 Observed N of plates 151 20 13 7 . ܝ ܝ ܝ ܚ ܘ ܚ ܘ ܝ . . . . 2 2 0 1 1 Using these observed numbers and assuming a Poisson distribution we have calculated the expected number of plates for each category (each row of the table above is a category). We have used the Chi-square statistic to test whether the observed number of plates per category are in agreement with the Poisson distribution. Note that to respect the mathematical assumptions of the Chi-square, we have combined into one all categories with 6 or more colonies per plate.
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