Before the furniture store began its ad campaign, it averaged 241 customers per day. The manager is investigating if the average has changed since the ad came out. The data for the 12 randomly selected days since the ad campaign began is shown below:  256, 250, 270, 244, 268, 237, 236, 226, 244, 247, 253, 246 Assuming that the distribution is normal, what can be concluded at the αα = 0.05 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion  The null and alternative hypotheses would be:       H0:H0:  ? μ p  Select an answer < = > ≠         H1:H1:  ? μ p  Select an answer > < ≠ =     The test statistic ? z t  =  (please show your answer to 3 decimal places.) The p-value =  (Please show your answer to 4 decimal places.) The p-value is ? ≤ >  αα Based on this, we should Select an answer fail to reject accept reject  the null hypothesis. Thus, the final conclusion is that ... The data suggest the population mean is not significantly different from 241 at αα = 0.05, so there is sufficient evidence to conclude that the population mean number of customers since the ad campaign began is equal to 241. The data suggest the populaton mean is significantly different from 241 at αα = 0.05, so there is sufficient evidence to conclude that the population mean number of customers since the ad campaign began is different from 241. The data suggest that the population mean number of customers since the ad campaign began is not significantly different from 241 at αα = 0.05, so there is insufficient evidence to conclude that the population mean number of customers since the ad campaign began is different from 241. Interpret the p-value in the context of the study. There is a 7.86759776% chance of a Type I error. There is a 7.86759776% chance that the population mean number of customers since the ad campaign began is not equal to 241. If the population mean number of customers since the ad campaign began is 241 and if you collect data for another 12 days since the ad campaign began, then there would be a 7.86759776% chance that the population mean would either be less than 233.9 or greater than 248.1. If the population mean number of customers since the ad campaign began is 241 and if you collect data for another 12 days since the ad campaign began, then there would be a 7.86759776% chance that the sample mean for these 12 days would either be less than 233.9 or greater than 248.1. Interpret the level of significance in the context of the study. There is a 5% chance that there will be no customers since everyone shops online nowadays. There is a 5% chance that the population mean number of customers since the ad campaign began is different from 241. If the population mean number of customers since the ad campaign began is different from 241 and if you collect data for another 12 days since the ad campaign began, then there would be a 5% chance that we would end up falsely concuding that the population mean number of customers since the ad campaign is equal to 241. If the population mean number of customers since the ad campaign began is 241 and if you collect data for another 12 days since the ad campaign began, then there would be a 5% chance that we would end up falsely concuding that the population mean number of customers since the ad campaign began is different from 241.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section: Chapter Questions
Problem 13PT
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I AM RESUBMITTING THIS QUESTION FOR SUBPARTS 4, 5, 6, AND 7. THANK YOU.

 

Before the furniture store began its ad campaign, it averaged 241 customers per day. The manager is investigating if the average has changed since the ad came out. The data for the 12 randomly selected days since the ad campaign began is shown below: 

256, 250, 270, 244, 268, 237, 236, 226, 244, 247, 253, 246

Assuming that the distribution is normal, what can be concluded at the αα = 0.05 level of significance?

  1. For this study, we should use Select an answer t-test for a population mean z-test for a population proportion 
  2. The null and alternative hypotheses would be:     

 H0:H0:  ? μ p  Select an answer < = > ≠       

 H1:H1:  ? μ p  Select an answer > < ≠ =    

  1. The test statistic ? z t  =  (please show your answer to 3 decimal places.)
  2. The p-value =  (Please show your answer to 4 decimal places.)
  3. The p-value is ? ≤ >  αα
  4. Based on this, we should Select an answer fail to reject accept reject  the null hypothesis.
  5. Thus, the final conclusion is that ...
    • The data suggest the population mean is not significantly different from 241 at αα = 0.05, so there is sufficient evidence to conclude that the population mean number of customers since the ad campaign began is equal to 241.
    • The data suggest the populaton mean is significantly different from 241 at αα = 0.05, so there is sufficient evidence to conclude that the population mean number of customers since the ad campaign began is different from 241.
    • The data suggest that the population mean number of customers since the ad campaign began is not significantly different from 241 at αα = 0.05, so there is insufficient evidence to conclude that the population mean number of customers since the ad campaign began is different from 241.
  6. Interpret the p-value in the context of the study.
    • There is a 7.86759776% chance of a Type I error.
    • There is a 7.86759776% chance that the population mean number of customers since the ad campaign began is not equal to 241.
    • If the population mean number of customers since the ad campaign began is 241 and if you collect data for another 12 days since the ad campaign began, then there would be a 7.86759776% chance that the population mean would either be less than 233.9 or greater than 248.1.
    • If the population mean number of customers since the ad campaign began is 241 and if you collect data for another 12 days since the ad campaign began, then there would be a 7.86759776% chance that the sample mean for these 12 days would either be less than 233.9 or greater than 248.1.
  7. Interpret the level of significance in the context of the study.
    • There is a 5% chance that there will be no customers since everyone shops online nowadays.
    • There is a 5% chance that the population mean number of customers since the ad campaign began is different from 241.
    • If the population mean number of customers since the ad campaign began is different from 241 and if you collect data for another 12 days since the ad campaign began, then there would be a 5% chance that we would end up falsely concuding that the population mean number of customers since the ad campaign is equal to 241.
    • If the population mean number of customers since the ad campaign began is 241 and if you collect data for another 12 days since the ad campaign began, then there would be a 5% chance that we would end up falsely concuding that the population mean number of customers since the ad campaign began is different from 241.
Expert Solution
Step 1 :

Part 4) 

P-value decision rule is as follows;

If p value  ≤ significance level , then we reject null and supports alternative .
If p value  > significance level , then we fail to reject null that is we support null and reject alternative.

Here , p-value  = 0.0786759776 and Significance level ,α = 0.05.

So , p-value > significance level so when this is case we fail to reject null hypotheses.

Part 5)

Here we fail to reject null it simply means that we accept null and reject alternative hypotheses.

The data suggest that the population mean number of customers since the ad campaign began is not significantly different from 241 at α = 0.05, so there is insufficient evidence to conclude that the population mean number of customers since the ad campaign began is different from 241.

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