Below are the half reactions for sulfate reduction using acetate as a source of electrons, energy, and carbon. 2CO₂ + 8e-> CH3COO (-0.29 volts) SO4 + 8e-> H₂S (-0.22 volts) Using the information given, calculate the AE for this reaction, balance the full reaction to determine n, the number of electrons transferred when 86 moles of SO4²- are reduced. Finally, use the simplified Nernst Equation AG-nFAE, where F = 96.5 kJ (mol e x V)-1

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Chapter19: Electrochemistry
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Problem 19.123QP: An aqueous solution of an unknown salt of gold is electrolyzed by a current of 2.75 amps for 3.39...
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Below are the half reactions for sulfate reduction using acetate as a source of electrons, energy, and carbon.
• 2CO₂ + 8e-> CH3COO(-0.29 volts)
• SO4² +8e-> H₂S (-0.22 volts)
Using the information given, calculate the AE for this reaction, balance the full reaction to determine n, the number of electrons transferred when 86 moles of SO42- are
reduced. Finally, use the simplified Nernst Equation
AG=-nFAE, where F = 96.5 kJ (mol e¯ x V)-1
Transcribed Image Text:Below are the half reactions for sulfate reduction using acetate as a source of electrons, energy, and carbon. • 2CO₂ + 8e-> CH3COO(-0.29 volts) • SO4² +8e-> H₂S (-0.22 volts) Using the information given, calculate the AE for this reaction, balance the full reaction to determine n, the number of electrons transferred when 86 moles of SO42- are reduced. Finally, use the simplified Nernst Equation AG=-nFAE, where F = 96.5 kJ (mol e¯ x V)-1
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