Below is the resolved absorption spectrum of HBr forthe vibrational transition v = 0→ V = 1; determine: (a)the effective spring constant for the molecular bond35and (b) the bond length. (c) Repeat for both the HCl37and H Cl spectra. (d) Based upon these results,explain your prediction regarding which molecule hasthe "strongest" bond and then explain whether yourprediction is confirmed by looking up the correspondingbond dissociation energies.✓20.3000.3100.3200.3300.340Energy (eV)

Our usual method of determining the effective spring constant and bond length from the resolved…

Answered: Below is the resolved absorption…

Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Chapter9: Atomic Absorption And Atomic Fluorescence Spectrometry

Section: Chapter Questions

Problem 9.8QAP

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Suppose you were seeking the presence of (planar) S03 molecules in the microwave spectra of interstellar gas clouds. (a) You would need to know the rotational constants A and B. Calculate these parameters for 32S16O3, for which the S-O bond length is 143 pm. (b) Could you use microwavespectroscopy to distinguish the re lative abundances of 32S16O3 and 33S16O3?
The fundamental vibrational wavenumber, ?, of the H19F molecule is at 4138.3 cm-1. Calculate the force constant of the H-F bond in units of N m-1.
Given that the maximum molar absorption coefficient of a molecule containing a carbonyl group is 30 dm3 mol−1 cm−1 near 280 nm, calculate the thickness of a sample that will result in (i) half the initial intensity of radiation, (ii) one tenth the initial intensity.
The pure rotational microwave spectrum (Topic 11B) of HCl has absorption lines at the following wavenumbers (in cm−1): 21.19, 42.37, 63.56, 84.75, 105.93, 127.12 148.31 169.49, 190.68, 211.87, 233.06, 254.24, 275.43, 296.62, 317.80, 338.99, 360.18, 381.36, 402.55, 423.74, 444.92, 466.11, 487.30, 508.48. Calculate the rotational partition function at 25 °C by direct summation.
The wavenumber of the fundamental vibrational transition of Cl2 is 565 cm-1, Calculate the force constant of the bond.
The molecule with strong absorptions at 1800 and 1760 cm ^ -1 is:
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The fundamental line (v′′ = 0 → v′ = 1) in the infrared absorption spectrum of 12C16O is at2143 cm–1 and the first overtone, (v′′ = 1 → v′ = 2), at 2117 cm–1. Determine Ve and XeVe for 12C16O.
a.) The spacings of the rotational fine structure lines of carbon dioxide 12C16O2 are determined from IR spectroscopy to be 0.7604 cm-1. Calculate the C=O bond length of the molecule (given masses: m(12C) = 12 amu, m(16O) = 15.9949 amu).Ans = ______ Angstroms b.) Suppose that the wavenumber of the J = 1 ← 0 rotational transition of 1H79Br considered as a rigid rotor was measured to be 17.89 cm-1, what is the bond length? Ans = ____ Angstroms When the moment of interia is 3.132x10^-47 kg*m^2(Given the isotopic masses:(m(79Br) = 78.9183 amu, m(81Br) = 80.9163 amu)
Suppose the C=O group in a peptide bond can be regarded as isolated from the rest of the molecule. Given the force constant of the bond in a carbonyl group is 908 N m-1, calculate the vibrational wavenumber of (a) 12C=16O.(b) 13C=16O.
Suggest a reason why the replacement of 12C by 13C in CO2 affects some of its vibrational frequencies but not all.

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