Answer the last two portion with the red asterisk (*) POULTRY PROBLEMProblem: A virologist is interested in studying the effects of 2 preselected differentculture media and 2 preselected different times on the growth of a particular virus.She performs a balanced design with 6 plates for each of the treatmentcombinations. The 24 measurements were taken in a completely randomizedorder.Test for factor A: (if necessary)Ho: (in symbols and words)Ha: (in symbols and words)Test statistic formula:Value of the test statistic:推維維推p-value:Decision:Conclusion:MediumTimeData1227.538.027.229.737.615.440.026.821.037.328.620.840.931.119.111838.81227.125.42Test for factor B: (if necessary)Ho: (in symbols and words)Ha: (in symbols and words)Test statistic formula:1829.330.631.632.832.533.6Describe the relationship of the factors using the plot below.Value of the test statistic:p-value:Decision:Cousion:* Explain briefly how you should proceed given the result of recent hypothesis tests.If all assumptions of parametric test were satisfied,201012 hrs18 hrs* Based on R outputs on the sheet provided, summarize your insights aboutthe effects of 2 different culture media and 2 different times on the growthof a particular virus.1.02.0Medium* Determine whether they exhibit strong, intermediate or no interaction. Provide explanation.Test the assumption of the parametric test at 5% level of significance.Testp-valueConclusionR outputsHomogeneity of VariancesShapiro-Wilk Normality Test*TC1:p-valueConclusiondata: Medium 1 & Time 12data:Medium 1& Time 18Shapiro-Wilk normality testW = 0.93239,p-value = 0.5987data:Shapiro-Wilk normality testW = 0.91981,*TC2:*TC3:*TC4:p-value = 0.504Medium 2 & Time 12data:Medium 2 & Time 18*TC – Treatment CombinationShapiro-Wilk normality testW = 0.86098p-value = 0.2318Shapiro-Wilk normality testW= 0.96619p-value = 0.8503What is the most appropriate analysis given the results on testing of assumptions?Justify your answer.Levene's Test for Homogeneity of Variance (center = "mean")Df F value Pr (>F)group5.474 0.006521summary(aov(wk8_data$Data~wk8_data$Medium*wk8_data$Time))Df Sum Sq Mean Sq F valuePr(>F)0.531wk8_data$Mediumwk8_data$Time13.83.80.4061 633.5633.5 68.385 6.96e-08 ***wk8_data$Medium:wk8_data$Time1233.8233.8 25.235 6.51e-05 ***Residuals20 185.39.3Suppose all assumption of parametric test were satisfied, perform necessaryparametric tests of hypothesis at 5% level of significance.Signif. codes: 0 ****' 0.001 **' 0.01 **' 0.05 '.' 0.1 ' ' 1Test for Interaction of factor A and BAnalysis of VarianceHo: (in symbols and words)Ha: (in symbols and words)Test statistic formula:Value of the test statistic:Df Sum Sq Mean Sg F value871.0Pr (>F)31.34 9.35e-08 ***Treatment CombinationResiduals3290.3220185.39.26p-value:Decision:Conclusion:Signif. codes:0 ****! 0.001 '**' 0.01 '*0.05 '.' 0.1 ' 1Kruskal-Wallis Rank Sum Testdata:wk8 data$Data by Treatment CombinationsKruskal-Wallis chi-squared = 19.007, df = 3, p-value = 0.0002725Data

For all quantities of subsequent explanatory variables, the interaction term is used to estimate the…

blem: rologis studying the elect culture media and 2 preselected different times on the growth of a particular virus. She performs a balanced design with 6 plates for each of the treatment combinations. The 24 measurements were taken in a completely randomized order. Medium Time 12 1 2 륨 18 12 18 9 8 2 27.5 38.0 27.2 29.3 24 29.7 37.6 27.1 30.6 Describe the relationship of the factors using the plot below. 15.4 40.0 26.8 31.6 Data 21.0 37.3 28.6 32.8 20.8 40.9 31.1 32.5 12 hrs 18 hrs 19.1 38.8 25.4 33.6 Test for factor A: (if necessary) Ho: (in symbols and words) Ha: (in symbols and words) Test statistic formula: Value of the test statistic: p-value: Decision: Conclusion: Test for factor B: (if necessary) Ho: (in symbols and words) Ha: (in symbols and words) Test statistic formula: Value of the test statistic: p-value: Decision: Conclusion: * Explain briefly how you should proceed given the result of recent hypothesis tests. If all assumptions of parametric test were satisfied, * Based on R outputs on the sheet provided, summarize your insights about the effects of 2 different culture media and 2 different times on the growth of a particular virus.

blem: rologis studying the elect culture media and 2 preselected different times on the growth of a particular virus. She performs a balanced design with 6 plates for each of the treatment combinations. The 24 measurements were taken in a completely randomized order. Medium Time 12 1 2 륨 18 12 18 9 8 2 27.5 38.0 27.2 29.3 24 29.7 37.6 27.1 30.6 Describe the relationship of the factors using the plot below. 15.4 40.0 26.8 31.6 Data 21.0 37.3 28.6 32.8 20.8 40.9 31.1 32.5 12 hrs 18 hrs 19.1 38.8 25.4 33.6 Test for factor A: (if necessary) Ho: (in symbols and words) Ha: (in symbols and words) Test statistic formula: Value of the test statistic: p-value: Decision: Conclusion: Test for factor B: (if necessary) Ho: (in symbols and words) Ha: (in symbols and words) Test statistic formula: Value of the test statistic: p-value: Decision: Conclusion: * Explain briefly how you should proceed given the result of recent hypothesis tests. If all assumptions of parametric test were satisfied, * Based on R outputs on the sheet provided, summarize your insights about the effects of 2 different culture media and 2 different times on the growth of a particular virus.

College Algebra

7th Edition

ISBN:9781305115545

Author:James Stewart, Lothar Redlin, Saleem Watson

Publisher:James Stewart, Lothar Redlin, Saleem Watson

Chapter9: Counting And Probability

Section9.3: Binomial Probability

Problem 1E: A binomial experiment is UDC in which there are exactly __________ outcome. One outcome is called...

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A binomial experiment is UDC in which there are exactly __________ outcome. One outcome is called __________ , and the other is called ___________.
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In the search for a cure for the Coronavirus, it is important to determine what proportion of the population has antibodies, which would likely make them immune or less susceptible to the effects of the disease. According to an article in Politico published on April 26, 2022, 60% of Americans currently have detectible antibodies for Covid-19. A researcher thinks that more than 60% of Americans currently have antibodies for Covid-19. Suppose that the researcher takes a simple randomsample of 1200 Americans, tests their blood, and find that 750 of them have antibodies. Use a 0.05 significance level to test the researcher’s claim.
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