22 Both over-the-counter niacin and the prescription drug Lipitor are known to lower blood cholesterol levels. Inone double-blind study Lipitor outperformed niacin. The 95% confidence interval estimate of the difference inmean cholesterol level lowering was (18, 41). Which of the following is a reasonable conclusion?Niacin lowers cholesterol an average of 18 points, while Lipitor lowers cholesterol an average of 41 points.O There is a 0.95 probability that Lipitor will outperform niacin in lowering the cholesterol level of any given individual.O None of the above.O There is a 0.95 probability that Lipitor will outperform niacin by at least 23 points in lowering the cholesterol level of anygiven individual.O We should be 95% confident that Lipitor will outperform niacin as a cholesterol-lowering drug.

Both over-the-counter niacin and the prescription drug lipitor are known to lower blood cholesterol…

Answered: Both over-the-counter niacin and the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A researcher surveys 50 individuals in Smithville and 40 in Amherst, finding that 30% of smithville residents moved last year, while only 22% of Amherst residents did. Is there enough evidence to conclude that mobility rates in the two communities differ? Use a two-tailored alternative, and a=0.10. Again, find the p-value and a 90% confidence interval for the difference in proportions
Do crows remember the faces of people who bother them? A volunteer wearing a caveman mask was scolded by 158 out of 444 crows he encountered, and the crows scolded a person in the neutral mask in 109 out of 922 encounters. Load the data above into StatKey, and use the percentile method to find a 90% confidence interval for the difference in the proportion of crow scoldings between volunteers wearing the caveman mask and those wearing the neutral mask. What is the left endpoint and right endpoint?
According to a report on sleep deprivation by the Centers for Disease Control and Prevention, the proportion of California residents who reported insufficient rest or sleep during each of the preceding 30 days is 8.0%, while this proportion is 8.8% for Oregon residents. These data are based on simple random samples of 11,545 California and 4,691 Oregon residents. Calculate a 95% confidence interval for the difference between the proportions of Californians and Oregonians who are sleep deprived and interpret it in context of the data.
The Vegetarian Resource Group commissioned Harris Poll in 2016 to conduct a nationally representative online poll of 2,015 adults aged 18 and over. They found that 3.3% of the respondents identified as vegetarian. a. Construct and interpret a 95% confidence interval for the proportion of vegetarians. b. Explain why a 90% confidence interval for the proportion of vegetarians will be wider/narrower than the one in (a.) Construct the interval to confirm c. Explain why the interval will be wider/narrower than the one in (a) if the sample size changed to n=300. Construct the interval to confirm
in clinical trials of allergy medicine clarinex 5 mg it was reported that 50 out of 1655 individuals in clarinex group and 31 out of 1652 individuals in placebo group experienced dry mouth as a possible side effect of their respectivetreatments. the results of a 95% confidence interval for the proption of clarinex users who ecperince dry mouth munus the proportion of placebo takers who ecpericened dry mouth are ( 0.0009,0.0220) interpret the interval in context
A random sample of 180 men indicated that 50 were smokers, and a random sample of 150 women surveyed indicated that 39 smoked. Construct a 98% confidence interval for the true difference in proportions of male and female smokers.
A research group studying cell phone habits asked the question “Do you ever use your cell phone to make a payment at a convenience store?” to people selected from two random samples of cell phone users. One sample consisted of older adults, ages 35 years and older, and the other sample consisted of younger adults, ages 18 years to 34 years. The proportion of people who answered yes in each sample was used to create a 95 percent confidence interval of (0.097,0.125)(0.097,0.125) to estimate the difference (younger minus older) between the population proportions of people who would answer yes to the question. Which of the following is the best description of what is meant by 95 percent confidence? In repeated random sampling with the same sample size, approximately 95% of the sample proportions from the younger group will be between 0.097 and 0.125 greater than the sample proportion from the older group. A In repeated random sampling with the same sample size,…
A random sample of 240 adults over the age of 40 found that 144 would use an online dating service. Another random sample of 234 adults age 40 and under showed that 131 would use an online dating service. Assuming all conditions are met, which of the following is the standard error for a 90 percent confidence interval to estimate the difference between the population proportions of adults within each age group who would use an online dating service?
In a simple random sample of 38 bulbs, 25 gives a good glow, What is a 85% score Confidence interval CI for the true proportion of the bulbs that gives good glow
In a study of the accuracy of fast food drive-through orders, restaurant a had 346 accurate orders and 61 that were not accurate. Construct a 90% confidence interval estimate of the percentage of orders that are not accurate. Compare the results from part A to this 90% confidence interval for the percentage of orders that are not accurate at restaurant B: 0.132< P < 0.189. What do you conclude?
When a recent survey asked subjects whether it should or should not be the government's responsibility to impose strict laws to make industry do less damage to the environment, 1200 of 1700 subjects said yes. Construct the 95% confidence interval. Can you conclude whether or not a majority or minority of the population would answer yes?
A national poll asked, “how would you describe your job situation now compared to before the Covid-19 outbreak??” The results showed that 24% of workers in the U.S. report having a worse job situation now compared to before the COVID-19 outbreak began with a margin of error of 1.8%. (a) Assume the margin of error is reported for a 95% confidence interval, use this information to calculate a 95% confidence interval for the population proportion of persons who have a worse job situation now compared to before the outbreak. (b) Based on the calculated confidence interval, is there evidence that at least 1 out of every 4 (25%) Americans have a worse job situation not compared to before the outbreak? Explain why briefly. (c) What was the sample size of this poll? (d) If you wanted a 99% confidence interval for the same study, would your margin of error be greater than, equal to, or less than 1.8%?

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