Buret contains NaOH solution *Sodium hydroxide solution: To 1 part reagent grade NAOH add 1 part distilled, carbon dioxide-free water by weight Erlenmeyer flask contains about 9mL of the acid and about 10 ml of distilled water made recently free from CO2 by boiling. DATA SHEET II Final Reading HCI Initial Reading HCI 9.4 Final Reading NaOH Initial Reading NaOH 10.65 10.55 1 mL HCI 1 mL NAOH Mean Values: 1 mL HCI = . 1 mL NAOH = mL NAOH mL HCL mL NaOH mL HCL _mL NaOH _mL HCL COMPUTATION:

Buret contains NaOH solution *Sodium hydroxide solution: To 1 part reagent grade NAOH add 1 part distilled, carbon dioxide-free water by weight Erlenmeyer flask contains about 9mL of the acid and about 10 ml of distilled water made recently free from CO2 by boiling. DATA SHEET II Final Reading HCI Initial Reading HCI 9.4 Final Reading NaOH Initial Reading NaOH 10.65 10.55 1 mL HCI 1 mL NAOH Mean Values: 1 mL HCI = . 1 mL NAOH = mL NAOH mL HCL mL NaOH mL HCL _mL NaOH _mL HCL COMPUTATION:

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter16: Reactions Between Acids And Bases

Section: Chapter Questions

Problem 16.102QE

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A different titration experiment using a 0.127M standardized NaOH solution to titrate a 27.67 mL solution with an unknown Molarity concentration (M) of sulfuric acid (H2SO4) gave the following molarities for 3 trials. Initial Burette Reading (mL) Final Burette Reading (mL) Delivered vol (mL) Acid Concentration (M) Trial 1 0.0358 Trial 2 0.0341 Trial 3 0.0331 From the 3 trials, determine the average Molarity concentration of the H2SO4 to 3 significant digits. Don't include a unit. From the 3 trials, determine the standard deviation of the Molarity concentration of the H2SO4 to 3 significant digits. Don't include a unit.From the 3 trials, determine the relative standard deviation of the Molarity concentration of the H2SO4 to 3 significant digits. Don't include a unit. Do you think the above experiment was accurate? Precise? Explain your answer using supporting values.
Consider a solution made by mixing 500.0 mL of 4.0M NH3 and 500.0mL of 0.40MAgNO3.Ag+ reacts with NH3, to form AgNH3+ and Ag(NH3)2+: Ag+(aq)+NH3(aq)AgNH3+(aq)+NH3(aq)⇌AgNH3+(aq)⇌Ag(NH3)2+(aq)K1=2.1×103K2=8.2×103 Determine the concentration of all species in solution. asap please.
it is time for the titration. You measure 15.0 mL of the H2C2O4 solution with a 100-mL graduated cylinder and add it to a 125-mL Erlenmeyer flask. Then you add two drops of the indicator, phenolphthalein, to the oxalic acid solution in the flask. You dispense the NaOH solution from the buret into the flask (while swirling the flask) until you reach the endpoint. At the endpoint, the solution in the flask turns light pink. You repeat the titration two additional times for a total of three trials. H2C2O4 (aq) + 2 NaOH (aq) --> Na2C2O4 (aq) + 2 H2O (l) (I) (II) (III) Volume of H2C2O4 used 15.00 mL 15.00 mL 15.00 mL Initial Buret Reading 0.00 mL 0.05 mL 0.10 mL Final Buret Reading 14.45 mL 14.38 mL 15.40 mL what Volume of NaOH is used ?
it is time for the titration. You measure 15.0 mL of the H2C2O4 solution with a 100-mL graduated cylinder and add it to a 125-mL Erlenmeyer flask. Then you add two drops of the indicator, phenolphthalein, to the oxalic acid solution in the flask. You dispense the NaOH solution from the buret into the flask (while swirling the flask) until you reach the endpoint. At the endpoint, the solution in the flask turns light pink. You repeat the titration two additional times for a total of three trials. H2C2O4 (aq) + 2 NaOH (aq) --> Na2C2O4 (aq) + 2 H2O (l) (I) (II) (III) Volume of H2C2O4 used 15.00 mL 15.00 mL 15.00 mL Initial Buret Reading 0.00 mL 0.05 mL 0.10 mL Final Buret Reading 14.45 mL 14.38 mL 15.40 mL Volume NaOH used ________mL ________mL ______mL Moles NaOH _______M ________M _________M…
A different titration experiment using a 0.122M standardized NaOH solution to titrate a 26.48 mL solution with an unknown Molarity concentration (M) of sulfuric acid (H2SO4) gave the following molarities for 3 trials. Initial Burette Reading (mL) Final Burette Reading (mL) Delivered vol (mL) Acid Concentration (M) Trial 1 0.0345 Trial 2 0.0334 Trial 3 0.0381 From the 3 trials, determine the average Molarity concentration of the H2SO4 to 3 significant digits. Don't include a unit.
Using table 3, answer the following questions. Concentration of HCl (M) 1.0M Volume HCl (mL) 5.01ml Concentration of NaOH (M) 1.0M Initial NaOH Volume (mL) 9.7mlml Final NaOH Volume (mL) 7.00 Total Volume of NaOH Used (mL) 2.7ml Moles of NaOH needed to neutralize 5.0 mL of 1.0M HCl (mol): Grams of HCl neutralized (g): NaOH volume difference between back titration and control (mL): Grams of HCl neutralized by NaOH volume difference (g):
This is about determinition of acid content in vinegar through titration, please answer the questions. Please answer only the items nummber 4-5. i only put other questions for guide. 1. What is the purpose of standardization? 2. What is the primary standard used (name and formula)? ANS: KHP 3. Suppose that the KHP is not completely dry. Will the reported molar concentration of the sodium hydroxide solution be higher, lower, or unaffected? Explain. 4. In preparing the buret for titration the final rinse is with the NaOH titrant rather than with distilled water. Explain. 5. The procedure suggests the addition of only 2 drops of phenolphthalein. What will be the effect to the analysis if larger amount of phenolphthalein is added?
Determine the Concentration of Ethanoic Acid in Vinegar Equipment / Apparatus:  250-mL conical flasks  Clamp  Burette  Graduated cylinder  Pipette Reagents / Materials:  Vinegar  Phenolphthalein indicator  0.2 M NaOH (standardized) Calculation: Molarity (M) of ethanoic acid  The average measured volume of the NaOH from titration: Average volume of NaOH used = (21.5ml + 21.5ml + 21.6ml) / 3 =21.5ml No of mole of NaOH = Concentration of NaOH (0.2M) × Average volume of NaOH used When an acid is completely neutralized: No of moles of CH3COOH = No of moles of NaOH Using the moles of CH3COOH, the molarity of ethanoic acid in the 5.0-mL sample of vinegar is calculated: Molarity (M) CH3COOH = moles CH3COOH / volume of vinegar (0.005 dm3). Calculation: Mass / Volume Percent (m/v) of ethanoic acid To calculate the percent (m/v) of CH3COOH in vinegar, we convert the moles of ethanoic acid to grams using the molar mass of ethanoic acid, 60.1 g/mole. Mass of CH3COOH =…
Express the concentration of acetic acid in both samples as % by mass of acetic per 100mL of solution given : %= mass/ volumex100% Given: NaOH vs CH3COOH Burette solution is NaOH and the pipette solution is 5.0 mL of Vinegar Titration Initial burette reading Final burette reading Volume of NaOH consumed Average volume of NaOH Approximate 0.0 mL 20.1 mL 20.1 mL 20.3 mL Titration 1 0.0 mL 20.9 mL 20.9 mL Titration 2 0.0 mL 20.0 mL 20.0 mL To find the average volume Average volume = 20.1 mL + 20.9 mL + 20.0 mL320.1 mL + 20.9 mL + 20.0 mL3 = 20.3 mL Concentration of Vinegar = Volume of NaOH * Concentration of NaOHVolume of vinegarVolume of NaOH * Concentration of NaOHVolume of vinegar = 20.3 mL * 0.0647 M5.0 mL20.3 mL * 0.0647 M5.0 mL = 0.2627 M Concentration of NaOH = Volume of H2SO4 * Concentration of H2SO4Volume of NaOHVolume of H2SO4 * Concentration of…
Give typed solution A student analyzed a CaCO3 antacid tablet by neutralizing the base with an excess of .60 M HCL and back-titrating the excess with .50M NaOH. He recorded the following data: mass of tablet = 1.3g amount of active ingredient CaCO3 per label = 500 mg volume of HCl added: 25 mL initial buret reading : 34 mL final buret reading : 47.4 mL If the concentration of the provided HCl is actually higher than .60M, would the determined mass of CaCO3 in the antacid tablet be too high or too low?
Using the stock solution concentrations of 0.20 M Fe3+ and 2.0*10^-3 M SCN-, calculate the following concentrations of Fe3+ and SCN- after they have been mixed. (Hint: use the dilution equation M1*V1 = M2*V2) 1. 2ml of Fe3+ and 0.25 ml SCN- 2. 2ml of Fe3+ and 1 ml SCN- 3. 2ml of Fe3+ and 2.25 ml SCN-
1. Calculate the moles of KHP you titrated for each trial. (KHP is KHC8H4O4). MW = 204.23 g/mol. Determine the number of moles of NaOH required to neutralizw the KHP. Use the mole-mole ratio provided inthe balanced equation. Place answers in data table 2(second picture format) 2. Calculate the volume, in mililiters, of NaOH used to neutralize the KHP. Convert to Liters. Place answers in data table 2. 3. Calculate the molarity of the NaOH solution in units of moles/liter. Place answers in data table 2.