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- 1252. WG compound weighing 1980 h pressure, yielding An unknown organi d 360 mg of water- 12 my s fully combusted at hig ‘9’30 g of carbon dioxide an hat is its empirical formula? A) CHO, B) CHO, ©) CHO, D) CH,0,Write the empirical formula for the hydrated KAl(SO4)2, based on moles of anhydrous KSI(SO4)2= 0.046 mol molar mass of H2O= 18g/ mol moles of H2O= 0.0444mol ratio pf moles H20 to moles of anhydrous KAI(SO4)2= 9.65/1 . Show all work including units. Hint: if the ratio of moles of H2O to moles of anhydrous KAl(SO4)2 was 4, then the empirical formula would be: KAl(SO4)2•4H2O.0.004 C8H7NO3, 15mL ethanol, 0.002mol NaBH4 was used. HCl was used to acidify. It was then extracted with ether. Then it was dried and a mass of 0.32g was obtained. What is the balanced equation of this synthesis, and what is the limiting reagent?
- Mass of Na2CO3.H2O (g) = 2.12g (g) Mass of the CaCl2.2H2O (g) = 1.98g Mass of the top funnel + filter paper (g) = 15.85g Mass of top funnel + filter paper + CaCO3 collected (g) = 17.81g CaCl2 + Na2CO3 ==== CaCo3 + 2NaCl Theoretical yield in moles and grams? Moles of reagent in excess left unreacted? Mass of precipitate? Experimental yield? Percent yield?A sample of an industrial waste water is analyzed and found to contain 16.5ppb Fe2+. How many grams of iron could be recovered from 1.81×103 kg of this waste water? Answer:_______ grams Feanother question The aluminum in a 1.200g sample of impure ammonium aluminum sulfate was precipitatedwith aqueous ammonia as the hydrous Al2O3 · XH2O. The precipitate was filtered and ignitedat 100°C to give anhydrous Al2O3, which weighed 0.2001 g. Express the result of this analysisin terms of % Al.
- 0.500 cm3 of concentrated H2O2 solution diluted exactly to 50.00 cm3 by water. 10.00 cm3 samples were taking out, and titrated by 0.02003 mol/dm3 KMnO4. The average of the individual result is 18.15 cm3. Give the molarity (mol/dm3) and the mass concentration (g/dm3) of the original concentrated H2O2 sample! Mr = 34.02 g/mol.About 200 grams of glucose was fermented with 20 grams of yeast inside a fermenting vessel for 2 weeks. Calculate the percent yield of ethyl alcohol in mL or %(v/v) if the actual yield of the fermentation set-up is at 84.50 mL alcohol. Assume the density of ethanol is at 0.789 g/mL. C6H12O6 + H2O --> 2C2H5OH + 2CO2 Molar Masses: Glucose: 180.156 g/mole; Ethanol: 46.07 g/mole Water: 18.00 g/mole Report your answers in two decimal places. Please include the unit. For example: 55.33%Mass of empty beaker=16.26Volume of CuSO4 5H2O=30mLMolarity of CuSO4 5H2O used=0.542Moles of CuSO4 5H2O=0.016Mass of aluminum foil used=0.26gMass of beaker and copper product=52.12gMass of copper metal product=35.86gMoles of Al used = 0.009636 molMoles of CuSO4 5H2O used=0.016mol Find the moles of copper product based on moles of Al.Find the moles of copper product based on moles of CuSO4 5H2OFind the limiting reactant in grams
- A hydrate [hydrates have the general formula AB • xH2O] is found to have the percentcomposition: Na = 19.17%, C = 10.00%, H = 4.17% and O = 66.6%. After heating to 100 oC todrive off the water of hydration, the percent composition is found to be: Na = 27.38%,C = 14.28%, H = 1.19% and O = 57.15%. From this data, determine the probable molecularformula for the hydrate if the molecular weight = 120 amu.A chemist carries out the reaction below and obtains 3.45g of iron Fe (Fe, MW=55.845g/mol). Fill in the blanks below to determine the percent yield of the reaction when 8.30g of Fe2O3 (MW= 159.69g/mol) and 3.50g of CO (MW=28.01G/mol)were used in the reaction. Fe2O3(s) + 3CO(g) = 2Fe(s) + 3CO2(g) Note that for two of the blanks, will be the same answer. 1. What would be the mass in grams of Fe produced based on the mass of Fe2O3 used? answer: (blank) 2. What would be the mass in grams of Fe produced based on the mass of CO used? answer: (blank) 3. What is the theoretical yield of Fe in grams? answer: (blank) 4. What is the limiting reagent? Enter the formula of compound. answer: (blank) 5. What is the percent yield of this reaction? answer: (blank)The mercury in a 1.1113-g sample was precipitated with an excess of paraperiodic acid, H5IO6: 5Hg2+ + 2H5IO6 → Hg5(IO6)2 + 10H+ The precipitate was filtered, washed free of precipitating agent, dried, and weighed, and 0.4733 g was recovered. Calculate the percentage of Hg2Cl2 in the sample. _______%