Bus Trip 200 180 160 140 120 100 80 60 40 20 2 8. 10 12 Time (hr) Given the position-time graph, find the displacement (distance and direction) of the bus: Given the position-time g the velocity (speed and di: the bus: 2. from t = 0.0 hr to t = 2.0 hr from t = 0.0 hr to t = а. а. %3D b. from t = 2.0 hr to t = 4.0 hr b. from t = 2.0 hr to t =. from t = 4.0 hr to t = с. from t = 4.0 hr to t = 6.0 hr С. d. from t = 8.0 hr to t = 10.0 hr d. from t = 6.0 hr to t = from t = 10.0 hr to t = 12.0 hr from t = 8,0 hr to t- e. e. %3D Position (km, north) 4.

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter2: Motion In One Dimension
Section: Chapter Questions
Problem 2P
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CHAPTER 3
Graphical Analysis of Motion
TRAS
PRACTICE EXERCISES
Bus Trip
200
180
160
140
120
100
80
60
40
20
4
6.
8
10 12
Time (hr)
Given the position-time graph, find
the displacement (distance and
direction) of the bus:
Given the position-time grap
the velocity (speed and direc
the bus:
2.
from t = 0.0 hr to t = 2.0 hr
from t = 0.0 hr to t = 2.0
a.
%3D
а.
%3D
b.
from t = 2.0 hr to t = 4.0 hr
b.
from t = 2.o hr to t = 4.0
%3D
C.
from t = 4.0 hr to t = 6.0 hr
from t =
%3D
%3D
C.
4.0 hr to t = 6.0
from t = 6.0 hr to t = 8.0
%3D
d.
from t = 8.0 hr to t = 10.0 hr
d.
%3D
%3D
%3D
from t = 10.o hr to t = 12.0 hr
from t = 8.0 hr to t = 10.
e.
%3D
е.
Position (km, north)
Transcribed Image Text:CHAPTER 3 Graphical Analysis of Motion TRAS PRACTICE EXERCISES Bus Trip 200 180 160 140 120 100 80 60 40 20 4 6. 8 10 12 Time (hr) Given the position-time graph, find the displacement (distance and direction) of the bus: Given the position-time grap the velocity (speed and direc the bus: 2. from t = 0.0 hr to t = 2.0 hr from t = 0.0 hr to t = 2.0 a. %3D а. %3D b. from t = 2.0 hr to t = 4.0 hr b. from t = 2.o hr to t = 4.0 %3D C. from t = 4.0 hr to t = 6.0 hr from t = %3D %3D C. 4.0 hr to t = 6.0 from t = 6.0 hr to t = 8.0 %3D d. from t = 8.0 hr to t = 10.0 hr d. %3D %3D %3D from t = 10.o hr to t = 12.0 hr from t = 8.0 hr to t = 10. e. %3D е. Position (km, north)
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