Answered: By applying 2.00 x 106 N/m2 shear…

By applying 2.00 x 106 N/m2 shear stress to a steel bar 2 m in length, calculated the shear bending distance Ax? (for steel S=8.3x108 N/m2) 7.3 mm 6.0 mm 1.5 mm 1.0 mm 4.8 mm

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter5: Further Applications Of Newton's Laws: Friction, Drag, And Elasticity

Section: Chapter Questions

Problem 38PE: A disk between vertebrae in the spine is subjected to a shearing force of 600 N. Find its shear...

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Concept explainers

Mechanical Properties of Solids

There are three types of matter- solid, liquid and gas. Out of them, solids have a rigid shaped and size. The intermolecular forces of attractions in solids are greatest. Mechanical properties are the physical properties of a material which it shows, when it is provided with certain amount of force or load. These properties are to be kept in mind for various purposes. When a force is applied to an object, the object may or may not get deformed depending upon its elastic property. But every time the object develops a restoring force against the force applied. This is commonly known as stress. If the object changes its dimensions due to the force applied it develops strain ( which is the ratio of change in dimension to the original dimension).

Question

By applying 2.00 x 106 N/m2 shear stress to a steel bar 2 m in length , calculated the shear bending distance Ax?
(for steel S=8.3x108 N/m2)
7.3 mm
6.0 mm
1.5 mm
O 1.0 mm
4.8 mm

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