By using the Laplace transform to solve the system x' = 3x - 3y + 2 We obtain: * None of them {y'²=-6x-t x(t)=[1/108] (133e^5t-28e^(-2t)+3-18t) and y(t)=[-1/108] (133e^6t+56e^5t+18t-81) x(t)=[1/108] (133e^6t-28e^(-3t)+3-18t) and y(t)=[-1)/108] (133e^6t+56e^(-3t)+18t-81) x(t)=[1/108] (133e^6t+8e^(-3t)+3-18t) and -¹ (5³) = y(t)=[-1/108](133e^6t+5e^(-3t)+8t-81) t^(6)/36 t^(5)/24 x(0) = 1 y(0) = -1 None of them t^(4)/6

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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*
By using the Laplace transform to solve the system
x' = 3x - 3y + 2
We obtain:
O None of them
*
y' = -6x-t
x(t)=[1/108] (133e^5t-28e^(-2t)+3-18t) and
y(t)=[-1/108] (133e^6t+56e^5t+18t-81)
x(t)=[1/108] (133e^6t-28e^(-3t)+3-18t) and
y(t)=[-1)/108] (133e^6t+56e^(-3t)+18t-81)
x(t)=[1/108] (133e^6t+8e^(-3t)+3-18t) and
t^(6)/36
t^(5)/24
x(0) = 1
y(0) = -1
y(t)=[-1/108](133e^6t+5e^(-3t)+8t-81)
None of them
t^(4)/6
Transcribed Image Text:* By using the Laplace transform to solve the system x' = 3x - 3y + 2 We obtain: O None of them * y' = -6x-t x(t)=[1/108] (133e^5t-28e^(-2t)+3-18t) and y(t)=[-1/108] (133e^6t+56e^5t+18t-81) x(t)=[1/108] (133e^6t-28e^(-3t)+3-18t) and y(t)=[-1)/108] (133e^6t+56e^(-3t)+18t-81) x(t)=[1/108] (133e^6t+8e^(-3t)+3-18t) and t^(6)/36 t^(5)/24 x(0) = 1 y(0) = -1 y(t)=[-1/108](133e^6t+5e^(-3t)+8t-81) None of them t^(4)/6
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