C. The probability that fawn will weigh exactly 3.1 kg is P(x = 3.1) =0 d. The probability that a newborn fawn will be weigh between 2.5 and 3.2 is P(2.5 < x < 3.2) = e. The probability that a newborn fawn will be weigh more than 3.02 is P(x > 3.02) = f. P(x > 2.6 |x< 2.8) =

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How do you do parts d, e, and f?
Suppose that the weight of an newborn fawn is Uniformly distributed between 2.3 and 3.9 kg.
Suppose that a newborn fawn is randomly selected. Round answers to 4 decimal places when
possible.
a. The mean of this distribution is 3.1
b. The standard deviation is 0.4619 v
c. The probability that fawn will weigh exactly 3.1 kg is P(x = 3.1) = 0
d. The probability that a newborn fawn will be weigh between 2.5 and 3.2 is P(2.5 < x <3.2) =
e. The probability that a newborn fawn will be weigh more than 3.02 is P(x > 3.02) =
f. P(x > 2.6 | x < 2.8) =
g. Find the 17th percentile. 2.572 v
Transcribed Image Text:Suppose that the weight of an newborn fawn is Uniformly distributed between 2.3 and 3.9 kg. Suppose that a newborn fawn is randomly selected. Round answers to 4 decimal places when possible. a. The mean of this distribution is 3.1 b. The standard deviation is 0.4619 v c. The probability that fawn will weigh exactly 3.1 kg is P(x = 3.1) = 0 d. The probability that a newborn fawn will be weigh between 2.5 and 3.2 is P(2.5 < x <3.2) = e. The probability that a newborn fawn will be weigh more than 3.02 is P(x > 3.02) = f. P(x > 2.6 | x < 2.8) = g. Find the 17th percentile. 2.572 v
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