4 Calculate AA'R and AG'R for the reaction CEH6() + 15/2 O2(g) - 6CO2(9) + 3H2O() at 298 K from the combustion enthalpy ofbenzene and the entropies of the reactants and products.combustion(kJ molr) Sm(J mol-1 K-1) Cem(J mol-1 K-1)-3,268AH136.0CeHe(n02(g)CO2(g)H2O)173.4205.229.4213.837.170.075.3AA R(kJ mol-1) =AG'R(kJ mol1) =

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Calculate AA'R and AG'R for the reaction CEH6() + 15/2 O2(g) - 6CO2(9) + 3H2O() at 298 K from the combustion enthalpy of benzene and the entropies of the reactants and products. AH combustion(kJ mol) S'm(J mol1 KCem(J mol1 K-1) CeHe( 02(g) CO2(g) H2O) -3,268 173.4 136.0 205.2 29.4 213.8 37.1 70.0 75.3 AA R(kJ mol-1) = 4G'R(kJ mol1) = %3!

Calculate AA'R and AG'R for the reaction CEH6() + 15/2 O2(g) - 6CO2(9) + 3H2O() at 298 K from the combustion enthalpy of benzene and the entropies of the reactants and products. AH combustion(kJ mol) S'm(J mol1 KCem(J mol1 K-1) CeHe( 02(g) CO2(g) H2O) -3,268 173.4 136.0 205.2 29.4 213.8 37.1 70.0 75.3 AA R(kJ mol-1) = 4G'R(kJ mol1) = %3!

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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