A solution is 1×10-4 M in NaF, Na,S, and Na3PO4 What would be the order of precipitation as a source of Pb2* is added gradually to the solution? - The relevant Ken values are: sp Kgp(PbF,) Ksp(PbS) Ksp[Pb3(PO,)2] = 1 x 10-54 = 4 x 10-8 = 7 x 10-29 %3D
A solution is 1×10-4 M in NaF, Na,S, and Na3PO4 What would be the order of precipitation as a source of Pb2* is added gradually to the solution? - The relevant Ken values are: sp Kgp(PbF,) Ksp(PbS) Ksp[Pb3(PO,)2] = 1 x 10-54 = 4 x 10-8 = 7 x 10-29 %3D
Chapter12: Gravimetric Methods Of Analysis
Section: Chapter Questions
Problem 12.26QAP
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![A solution is 1×10-4 M in NaF, Na,S, and Na,PO4
What would be the order of precipitation as a source of Pb2+ is added
gradually to the solution?
-
The relevant Ken values are:
-
Kp(PbF,)
Ksp(PbS)
Ksp[Pb3(PO4)2] = 1 x 10-54
= 4 x 10-8
= 7x 10-29
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa92a3480-fcc4-4f7a-baea-27b1357ae2bf%2F2768e289-3e19-444b-9cfc-400bf8b78bd3%2Fnl2zw3h_processed.png&w=3840&q=75)
Transcribed Image Text:A solution is 1×10-4 M in NaF, Na,S, and Na,PO4
What would be the order of precipitation as a source of Pb2+ is added
gradually to the solution?
-
The relevant Ken values are:
-
Kp(PbF,)
Ksp(PbS)
Ksp[Pb3(PO4)2] = 1 x 10-54
= 4 x 10-8
= 7x 10-29
%3D
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