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Calculate the AHn for the formation of 1 mole of PbOs) from lead metal and oxygen gas, given the following information: 1. AHran =-106.8 kJ Pb() + COle → PbOs) + C) 2G) + Ozie) → 2C0 AHan = -221.0 kJ 2. Calculate AHan for the reaction of lead(I1) chloride with chlorine gas to give 1 mole of lead(IV) chloride, given the following information: Pb + Pbis) PbClz) 2Clzie) → PbClam AHan = -359.4 kJ AHan = -329.3 kJ

Calculate the AHn for the formation of 1 mole of PbOs) from lead metal and oxygen gas, given the following information: 1. AHran =-106.8 kJ Pb() + COle → PbOs) + C) 2G) + Ozie) → 2C0 AHan = -221.0 kJ 2. Calculate AHan for the reaction of lead(I1) chloride with chlorine gas to give 1 mole of lead(IV) chloride, given the following information: Pb + Pbis) PbClz) 2Clzie) → PbClam AHan = -359.4 kJ AHan = -329.3 kJ

Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter5: Thermochemistry
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Part C: Hess's Law vs. Standard Enthalpies of Formation How do you know when a problem is a Hess's Law of Summation problem, instead of a standard enthalpy of formation problem? Hess's Law of Summation, as the name implies, is mostly used when you can combine or add multiple chemical equations together to obtain a specific chemical equation whose AH value is to be determined. Consequently, you cannot use Hess's Law of Summation when you don't have multiple chemical equations with known AH values, or you can't obtain those equations and AH values. A problem is a standard enthalpy of formation problem if you are given only one chemical equation to work with, AND all of the reactants and products that are known have standard enthalpies of formation listed in Table 6.3 on p. 246 (and also given on the periodic table info sheet on exam, and on page 4 of this worksheet). The standard enthalpy of formation method is very powerful in finding AH°ran! In any thermochemistry problem where AH"ran is not explicitly given, you should quickly check all of the substances in the balanced chemical equation to see if the AH°; values for all substances are given in the reference table. If they are all given, then you should calculate AH"rn using this method. If they are not all given, then either the problem does not require AH°rxn, or you have to use Hess's Law or calorimetry to find it. Calculate the AHn for the formation of 1 mole of PbOfs) from lead metal and oxygen gas, given the following information: 1. Pb + CO → PbOts) + Cs) 2Cs) + Oze) → 2C0 AHnn = -106.8 kJ AHan = -221.0 kJ Calculate AHxn for the reaction of lead(II) chloride with chlorine gas to give 1 mole of lead(IV) chloride, given the following information: 2. Pbs) + Clzie) → PbClzs) Pb(s) + 2Cl2ie) → PbCla) AHan = -359.4 kJ AHn = -329.3 kJ
Transcribed Image Text:Part C: Hess's Law vs. Standard Enthalpies of Formation How do you know when a problem is a Hess's Law of Summation problem, instead of a standard enthalpy of formation problem? Hess's Law of Summation, as the name implies, is mostly used when you can combine or add multiple chemical equations together to obtain a specific chemical equation whose AH value is to be determined. Consequently, you cannot use Hess's Law of Summation when you don't have multiple chemical equations with known AH values, or you can't obtain those equations and AH values. A problem is a standard enthalpy of formation problem if you are given only one chemical equation to work with, AND all of the reactants and products that are known have standard enthalpies of formation listed in Table 6.3 on p. 246 (and also given on the periodic table info sheet on exam, and on page 4 of this worksheet). The standard enthalpy of formation method is very powerful in finding AH°ran! In any thermochemistry problem where AH"ran is not explicitly given, you should quickly check all of the substances in the balanced chemical equation to see if the AH°; values for all substances are given in the reference table. If they are all given, then you should calculate AH"rn using this method. If they are not all given, then either the problem does not require AH°rxn, or you have to use Hess's Law or calorimetry to find it. Calculate the AHn for the formation of 1 mole of PbOfs) from lead metal and oxygen gas, given the following information: 1. Pb + CO → PbOts) + Cs) 2Cs) + Oze) → 2C0 AHnn = -106.8 kJ AHan = -221.0 kJ Calculate AHxn for the reaction of lead(II) chloride with chlorine gas to give 1 mole of lead(IV) chloride, given the following information: 2. Pbs) + Clzie) → PbClzs) Pb(s) + 2Cl2ie) → PbCla) AHan = -359.4 kJ AHn = -329.3 kJ
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