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Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

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BuyFindarrow_forward

Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 7, Problem 103AE
Textbook Problem
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The bomb calorimeter in Exercise 102 is filled with 987 g water. The initial temperature of the calorimeter contents is 23.32°C. A 1.056-g sample of benzoic acid (∆Ecomb = −26.42 kJ/g) is combusted in the calorimeter. What is the final temperature of the calorimeter contents?

Interpretation Introduction

Interpretation: Final temperature of calorimeter content has to be calculated.

Concept introduction

Calorimeter: The apparatus used to measure heat that involved in chemical reactions.

Specific heat capacity: The specific heat capacity defined as quantity of heat required to raise temperature of the substance per unit mass.

Explanation of Solution

Explanation

Record the given data

Amount of water filled in bomb calorimeter =987g

Initial temperature of calorimeter content =23.320C

         Quantity of combusted benzoic acid =1.056g

             Change in energy of combustion =26.42 kJ/g

                                Specific heat of water = 4.18 J/0C

Total heat capacity of the calorimeter =6.660C (calculated in excercise number 102)

Amount of water in bomb calorimeter, Initial temperature of calorimeter, amount of combusted benzoic acid and change in energy of combustion recorded as shown above.

To calculate amount of heat released when 1.056 g benzoic acid combusted.

Heat released =1.056g×26.42 kJ/g

                      =27.90 kJ

The amount of heat released when 1.056g benzoic acid combusted has calculated by multiplying the value of energy change in combustion of benzoic acid with amount of benzoic acid. That is heat gain by water and calorimeter.

To calculate temperature change.

The heat gained by calorimeter which is equal to heat released when 1.056g benzoic acid combusted.

To covert: Gram into Kilogram

          9.87g = 0.987kg

    Heat gain=(4.18 kJ0C kg×0

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Chemistry: An Atoms First Approach
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