Question
Asked Nov 19, 2019
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Calculate the cell potential (Ecell) for the following lead concentration cell at 298 K.

 

 

Calculate the cell potential (Ecell) for the following lead concentration cell at 298 K
(-Pb
Рь(+)
Number
Ecell
[РЬ*]
[РЬ?]
Pb2-
0.005 M
[Pb2+1 1.75 M
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Calculate the cell potential (Ecell) for the following lead concentration cell at 298 K (-Pb Рь(+) Number Ecell [РЬ*] [РЬ?] Pb2- 0.005 M [Pb2+1 1.75 M

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Expert Answer

Step 1

Given that,

The concentration at negative pole = 0.005 M

The concentration at positive pole = 1.75 M

Overall concentration, Eº = 0 V

Now, the reaction is

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Pb(aq)+Pb (s)Pb (s)+Pb* (aq)

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Step 2

The transfer of electron is 2. Hence, the no.of mole is...

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Pb2 -log Pb29 0.0592 negative =E° cell positive 0.005 log 2 0.0592 =0- 1.75 0.075 V

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