Calculate the empirical formula of each substance from their spectrograms. 1) Co = 0.672 g, As 0.569g, O = 0.486g 2) naproxen ( The drug: Aleve) C = 73.03% H = 6.13 % O = 20.84 %

Q: 1. A platinum (II) compound , which is used to treat tumors, contains 65.0% Pt., 23.6% Cl, 9.35% N,…

A: As you have asked multiple question we will solve the first one for you .If you want answer to a…

Q: For a compound containing 181.351 g C, 36.5115 g a) the empirical formula C2H4N C3H7N C3H6N3 b) the…

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Q: Aspartame is an artificial sweetener that is 160 times sweeter than sucrose(table sugar) when…

A: Since you have posted a question question having multiple subparts, we are entitiled to answer only…

Q: 3: What is the simplest coefficient in front of NO when the equation below is balanced? NH3 + O2…

A: 3) given, NH3 + O2 → NO + H2O Simplest coefficient in front of NO when the equation is balanced = ?…

Q: A mineral sample is obtained from a region of the country that has high arsenic contamination. An…

A: The composition data given is,

Q: 2.491 g sample of a compound was combusted in excess oxygen to yield 7.321 g CO2 and 2.141 g H2O.…

A: First of all we have to calculate mass of C and H then if we substract total mass from mass of…

Q: A compound is analyzed and found to contain 12.1% carbon, 16.2% oxygen, and 71.7% chlorine (by…

A: Assuming 100 g of the compoun. Given : % of C = 12.1 %  % of O = 16.2 %  % of Cl = 71.7 %

Q: empirical formula

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Q: 41. Calculate the number of moles of carbon atoms present in each of the following samples. a. 1.271…

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Q: Without using a calculator, arrange the samples in order of increasing numbers of carbon atoms.…

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Q: 39. Calculate the number of molecules present in each of the following samples. a. 4.75 mmol of…

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Q: Which one of the following is an empirical formula? O C2F6 O H2SO2 O C2H402 O P4010

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Q: Caffeine, a stimulant in coffee and tea, a molar mass of 194.19 g/mol and a mass percentage…

A: Given,

Q: B. Calculate the number of moles contained in each of the following samples. 13) 1.06 x 1025 atoms…

A: Since you have posted a  question with sub-parts , we are entitled to answer the first three…

Q: Calculate the empirical formula of each substance from their spectrograms . 1) Co = 0.672g As =…

A: The emperical formula can be calculated by finding the number of moles.

Q: Combustion analysis of an unknown compound containing only carbon and hydrogen produced 0.2845 g of…

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Q: Aluminum, silicon and oxygen form minerals known as aluminosilicates. How many moles of aluminum are…

A: Mole is the amount of the substance that contains the same number of particles or atoms or…

Q: Lindane is one of the chlorinated pesticides the use of which is now restricted in the United…

A: The percentage composition of various elements are: 24.78% => carbon 2.08% => hydrogen 73.14%…

Q: The empirical formulae and molar masses of three compounds, A, B and C, are shown in Table 3.7.…

A: Empirical formula :-  The chemical formula which shows only the relative number of atoms of…

Q: Calculate the Molar mass of the following: 1. C14H29NO4S ( Penicillin – an antibiotic)     2.…

A: The molar mass or molecular weight of any compound is the sum of the mass of each element present in…

Q: Adipic acid contains 49.32% C, 43.84% O, and 6.85% H by mass. What is the empirical formula? Select…

A: Given: Adipic acid has 49.32 % C, 43.84 % O and 6.85% H by mass.

Q: A compound is 43.7% phosphorus and 56.3% oxygen. Calculate the empirical formula of the compound

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Q: Calculate the empirical formula of each substance from their spectrograms. 1) Co = 0.672 g , As =…

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Q: empirical formula of C4H10

A: Empirical formula of any compound is the formula which contains the atoms of each element in the…

Q: Calculate the empirical formula of a compound that has a percent composition of 3.7% H, 44.4% C, and…

A: Given data,Percent of H=3.7%Percent of C=44.4%Percent of N=51.9% The empirical formula of a compound…

Q: 8.00 g of iron when burned in air yields 11.44 g oxide. What is the empirical formula of this oxide?…

A: mass of oxygen= mass of oxide - mass of Fe(iron)

Q: Which of the following represents an empirical formula? a. C3H6O3 b. N2O2 c. CH4 d. C2H2Br2 e.…

A: The simplest ratio of the elements in the chemical compound is called empirical formula.The ratio…

Q: An oxide of gold thermally decomposes. A. 0.204 g sample of oxide is heated, forming 0.182 g of…

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Q: A compound has an empirical formula of CH3O and a molecular weight of 124 g, what is its molecular…

A: Empirical formula can be defined as the simplest whole number ratio of various atoms or elements…

Q: A compound is 54.53% C, 9.15% H, and 36.32% O by mass. What is its empirical formula? Insert…

A: Empirical formula of a substance represents the simplest ratio in which different elements are…

Q: A compound contains 76.47% Cr and 23.53% O. Calculate the empirical formula. Cr= 52.00 g/mole,  O =…

A: Given :-  Percent composition of Cr = 76.47 %  Percent composition of O = 23.53 %  MM of Cr = 52.00…

Q: What is the Empirical formula for C,H,,0; ? CHO CH,02 CH,0 C,H20,2

A: The given molecular formula is C6H12O6. Empirical formula is the simplest ratio of the elements…

Q: Urea, CO(NH2)2 is used as a fertilizer to provide nitrogen for the soil. How many moles of urea are…

A: Correct choices (B) , (C) & (E)

Q: 11. A compound was found to contain 59.9% C, 8.06% H, and 32.0% O by mass. What is the empirical…

A: Given the precentage composition by mass of carbon, hydrogen and oxygenin a compound.we are asked…

Q: 1.1 1. (a) A hydrocarbon (a compound that contains carbon and hydrogen only) contains 82.8% carbon…

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Q: Without doing any detailed calculations (but using a periodic table to give atomic weights), rank…

A: Each mole of any molecule contains Avogadro no of molecules i.e 6.023x10^23. It is true for every…

Q: Analysis of a compound with formula CxHyOz shows it is 53.711% in carbon and 10.517% in hydrogen by…

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Q: In order to determine the formula of CoCl.xH;O, a student heated 0.476 g of hydrate. The mass of…

A: First of all we have to calculate the weight of water that goes off after being heated.  Convert…

Q: What is the mass percent of carbon in the following compound? C4H10 O4

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Q: A compound is 53.31% C, 11.18% H, and 35.51% O by mass. What is its empirical formula? Insert…

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Q: An oxide of Mercury on analysis gave 20.3 g of Mercury and 1.7 g of Oxygen. What is the…

A: Given that:  Mass of mercury = 20.3 g  Molar mass of mercury = 200.6 g/mol Moles of mercury =…

Q: 51 Caffeine Caffeine, found in coffee, tea, chocolate, cola beverages is a highly popular stimulant…

A:

Q: The percentage composition by mass (to the nearest 0.1) of C in sugar, C8H10O7, is ______________.

A: The ratio of mass of particular atom to the total mass multiply by 100 is known as percentage by…

Q: A compound is found to contain 1.25g of Ge and 2.44g of Cl. What is the empirical formula of the…

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Q: How do I do this problem? Determine the empirical formula of a compound having the following…

A: Empirical formula: Formula of a compound in which the ratio of number of constituent elements is…

Q: What is the empirical formula of X

A: The empirical formula of the compound can be calculated with the help of percentage composition of…

Q: A compound is 53.31% C, 11.18% H, and 35.51% O by mass. What is its empirical formula? Insert…

A: Empirical formula represents the simplest whole number ratio of atoms of elements present in the…

Q: 968% nitrogen, 10.27% sulfur, and the rest is oxygen. What is the empirical formula of penicillin F?…

A: Carbon=53.827%  Sulphur = 10.27%  hydrogen = 6.453%  Nitrogen = 8.969%  oxygen = 100% - 79.519% =…

Q: Which compounds do not have the same empirical formula?   CO, CO2   C2H4O2, C6H12O6   C2H5COOCH3,…

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Q: Which of the following is equal to 1 mole of Ca atoms? * 6.022 x 10^22 molecules of Ca 6.022 x 10^23…

A: 1 mole of Ca atom is given  we have to convert it into atom because it’s not a molecule.

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.