  # Calculate the heat, in kilocalories, that is absorbed if 157g of ice at 0.0 degrees Celsius is placed in an ice bag, melts, and warms to body temperature of 37.0 degrees Celsius. The heat of fusion for water is 80. cal/g, or 334 J/g. The specific heat for water is 1.00 cal/g degrees Celsius, or 4.184 J/g degrees Celsius. Express your answer in 2 significant figures and include the appropriate units.

Question

Calculate the heat, in kilocalories, that is absorbed if 157g of ice at 0.0 degrees Celsius is placed in an ice bag, melts, and warms to body temperature of 37.0 degrees Celsius. The heat of fusion for water is 80. cal/g, or 334 J/g. The specific heat for water is 1.00 cal/g degrees Celsius, or 4.184 J/g degrees Celsius. Express your answer in 2 significant figures and include the appropriate units.

check_circleExpert Solution
Step 1

When an ice is melted and convert into liquid, some amount of energy is absorbed.

And this transformation follows:

Step 2

And these amounts of heat released can be calculated by using the formula:

Step 3

According to question:

Mass of ice/water = 157 g

Change in temperature in liquid water = (37.0 – 0) Celsius = 37.0 Celsius = 37.0 K

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