Calculate the heat released (kJ) in the reaction of 3.50 g of acetylene (C2H2) and excess hydrogen gas to form ethane gas: C2H2(g) + 2H2(g) –→ C2H6(g) Given: 2C2H2(g) + 502(g) → 4CO2(9) + 2H2O(g) AH = -2320 kJ/mol 2C2H6(g) + 702(g) → 4CO2(g) + 6H2O(g) AH = –3040 kJ/mol 2H2(g) + O2(g) → 2H2O(g) AH = -572 kJ/mol %3D

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A: Moles of ethane=11.1/30=0.37

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A: Since you have posted multiple questions, we are entitled to answer the first only.

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Q: I need help with 2 and 3

A: We are authorized to solve one question at a time. Please post rest of the questions separately.

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Q: exothermic

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