Calculate the Ka from the following data. + 2 H₂O H₂S 1.000 M start: equil: 2 H3O+ 0 0.0154 M 0.9923 M 0.0077 M The amount of H₂S that was converted into product is The stoichiometry tells us that 1 mol H₂S will give us mol of H30+1 M H₂S will give Thus, M H30+1 ][ Ka = D( 2² Ka = the concentration of [H3O+¹] is squared because its coefficient is 2 a. acetic b. hydrochloric c. phosphoric d. Al+3 g. HF(aq) h. CaCO3(s) i. OH-1 k. SO4² n. HPO4² 0. H₂PO4¹ P. CO3² r. H₂S u. H₂O(liq) v. H₂CO3 W. PO43 aa. 0.9923 bb. 0.0077 cc. 3 hh. 1.84 x 10-6 ii. 0.01250 j. H30+1 9. HCO3-1 + S-² 0 0.0077 M e. CO₂ x. HC₂H3O2 dd. 2 ee. 1 jj. 0.22100 kk. 0.05656 y. C₂H30₂-1 M S-² and 1. Mg+2 S. HS-1 M mol of S-2 and ff. 0.0154 f. CaF2(aq) m. Cl-1 t. S-2 z. 1x 10-14 gg. 3.95 x 10-3

Calculate the Ka from the following data. + 2 H₂O H₂S 1.000 M start: equil: 2 H3O+ 0 0.0154 M 0.9923 M 0.0077 M The amount of H₂S that was converted into product is The stoichiometry tells us that 1 mol H₂S will give us mol of H30+1 M H₂S will give Thus, M H30+1 ][ Ka = D( 2² Ka = the concentration of [H3O+¹] is squared because its coefficient is 2 a. acetic b. hydrochloric c. phosphoric d. Al+3 g. HF(aq) h. CaCO3(s) i. OH-1 k. SO4² n. HPO4² 0. H₂PO4¹ P. CO3² r. H₂S u. H₂O(liq) v. H₂CO3 W. PO43 aa. 0.9923 bb. 0.0077 cc. 3 hh. 1.84 x 10-6 ii. 0.01250 j. H30+1 9. HCO3-1 + S-² 0 0.0077 M e. CO₂ x. HC₂H3O2 dd. 2 ee. 1 jj. 0.22100 kk. 0.05656 y. C₂H30₂-1 M S-² and 1. Mg+2 S. HS-1 M mol of S-2 and ff. 0.0154 f. CaF2(aq) m. Cl-1 t. S-2 z. 1x 10-14 gg. 3.95 x 10-3

Physical Chemistry

2nd Edition

ISBN:9781133958437

Author:Ball, David W. (david Warren), BAER, Tomas

Publisher:Ball, David W. (david Warren), BAER, Tomas

Chapter8: Electrochemistry And Ionic Solutions

Section: Chapter Questions

Problem 8.81E: a The salt NaNO3 can be thought of as NaCl+KNO3KCl. Demonstrate that 0 values show this type of...

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