Calculate the lattice enthalpy of MgBr2 given the following data below: Enthalpy of sublimation of Mg = +148 kJ/mol lonization enthalpy of Mg to Mg²* = +2187 kJ/mol Enthalpy of vaporization of Br2(1) = + 31 kJ/mol Enthalpy of dissociation of Br2(g) = +193 kJ/mol Enthalpy of electron affinity of Br(g) = 331 kJ/mol Enthalpy of formation of MgBr2(s) from Mg(s) and Br2(1) = -524 kJ/mol O a. 2197 kJ/mol O b. 3745 kJ/mol C. 2421 kJ/mol O d. 2390 kJ/mol O e. 2752 kJ/mol

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Chapter12: The Solid State
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Calculate the lattice enthalpy of MgBr2 given the following data below:
Enthalpy of sublimation of Mg = +148 kJ/mol
lonization enthalpy of Mg to Mg²* = +2187 kJ/mol
Enthalpy of vaporization of Br2(1) = + 31 kJ/mol
Enthalpy of dissociation of Br2(g)
= +193 kJ/mol
Enthalpy of electron affinity of Br(g) = 331 kJ/mol
Enthalpy of formation of MgBr2(s) from Mg(s) and Br2(1) = -524 kJ/mol
O a. 2197 kJ/mol
O b. 3745 kJ/mol
Ос.
2421 kJ/mol
O d. 2390 kJ/mol
O e. 2752 kJ/mol
Transcribed Image Text:Calculate the lattice enthalpy of MgBr2 given the following data below: Enthalpy of sublimation of Mg = +148 kJ/mol lonization enthalpy of Mg to Mg²* = +2187 kJ/mol Enthalpy of vaporization of Br2(1) = + 31 kJ/mol Enthalpy of dissociation of Br2(g) = +193 kJ/mol Enthalpy of electron affinity of Br(g) = 331 kJ/mol Enthalpy of formation of MgBr2(s) from Mg(s) and Br2(1) = -524 kJ/mol O a. 2197 kJ/mol O b. 3745 kJ/mol Ос. 2421 kJ/mol O d. 2390 kJ/mol O e. 2752 kJ/mol
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