Asked Nov 2, 2019

Calculate the molarity of each of the following: 59.5 g LiCl in 250.0 mL of solution and 32.0 g NiSO4 in 200.0 mL of solution.


Expert Answer

Step 1


Molarity of LiCl:

Number of moles of LiCl = mass / molar mass = 59.5 g / 42.394 g mol-1 = 1.40...


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1.4035mol 5.614M L Molarity 250 x 10 Therefore, the molarity of LiCl is 5.614 M.


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