Calculate the molecules of oxygen required to react with 38.8 g of sulfur in the reaction below.25(6) + 302(g)→ 2SO3(g)O a. 1.09 x 1024 molecules oxygenOb.2.19 x 1024OC.4.86 x 1023 molecules oxygenO d.7.29 x 1025 molecules oxygenO e. 3.64 x 1023 molecules oxygenmolecules oxygen

Given, Amount of sulfur = 38.8 g Formula Used, Moles(n)=Given MassMolar Mass 1 mol has 6.023 x 1023…

Calculate the molecules of oxygen required to react with 38.8 g of sulfur in the reaction below. 2S(6) + 302(g) → 2S03() O a. 1.09 x 10-4 molecules oxygen Ob.2.19 x 1024 molecules oxygen OC.4.86 x 1023 molecules oxygen Od.7.29 x 1025 molecules oxygen Oe. 3.64 x 1025 molecules oxygen

Calculate the molecules of oxygen required to react with 38.8 g of sulfur in the reaction below. 2S(6) + 302(g) → 2S03() O a. 1.09 x 10-4 molecules oxygen Ob.2.19 x 1024 molecules oxygen OC.4.86 x 1023 molecules oxygen Od.7.29 x 1025 molecules oxygen Oe. 3.64 x 1025 molecules oxygen

Chemistry & Chemical Reactivity

10th Edition

ISBN:9781337399074

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter3: Chemical Reactions

Section3.9: Classifying Reactions In Aqueous Solution

Problem 1.5ACP

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Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

Calculate the molecules of oxygen required to react with 38.8 g of sulfur in the reaction below.
25(6) + 302(g)→ 2SO3(g)
O a. 1.09 x 1024 molecules oxygen
Ob.2.19 x 1024
OC.4.86 x 1023 molecules oxygen
O d.7.29 x 1025 molecules oxygen
O e. 3.64 x 1023 molecules oxygen
molecules oxygen

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