A 0.2750 g sample of soda ash required 24.10 mL of 0.1684 M HCl and a back-titration of 2.96 mL of 0.1005 M NaOH.  Calculate the %Na2CO3 in the sample. MM Na2CO3 = 105.99 MM HCl = 36.46

Organic Chemistry: A Guided Inquiry
2nd Edition
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Andrei Straumanis
Chapter27: Amines
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A 0.2750 g sample of soda ash required 24.10 mL of 0.1684 M HCl and a back-titration of 2.96 mL of 0.1005 M NaOH.  Calculate the %Na2CO3 in the sample.

MM Na2CO3 = 105.99

MM HCl = 36.46

 

 

Na,CO3
2HCI
→ 2NaCl + H20
CO2
+
NaOH + HCI
NaCI
H2O
Transcribed Image Text:Na,CO3 2HCI → 2NaCl + H20 CO2 + NaOH + HCI NaCI H2O
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