A 0.2750 g sample of soda ash required 24.10 mL of 0.1684 M HCl and a back-titration of 2.96 mL of 0.1005 M NaOH. Calculate the %Na2CO3 in the sample. MM Na2CO3 = 105.99 MM HCl = 36.46
A 0.2750 g sample of soda ash required 24.10 mL of 0.1684 M HCl and a back-titration of 2.96 mL of 0.1005 M NaOH. Calculate the %Na2CO3 in the sample. MM Na2CO3 = 105.99 MM HCl = 36.46
Organic Chemistry: A Guided Inquiry
2nd Edition
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Andrei Straumanis
Chapter27: Amines
Section: Chapter Questions
Problem 10E
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A 0.2750 g sample of soda ash required 24.10 mL of 0.1684 M HCl and a back-titration of 2.96 mL of 0.1005 M NaOH. Calculate the %Na2CO3 in the sample.
MM Na2CO3 = 105.99
MM HCl = 36.46
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