Generate a titration curve for 25.0 mL of 0.7233 M H;POs, with 1.256 M NAOH as the titrant, given the following total volumes of titrant dispensed. H3PO4 = H2PO: Kei = 7.11 x 103 H;PO: = HPO;? Ka2 = 6.32 x 10 HPO:? = PO, Ke3 = 4.50 x 10-3 V NaOH (mL): 0.00, 2.0, 12.0, 20.0, 30.0, 38.0, 45.0, 57.0, 66.0, 70.0, 85.0

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3.) Generate a titration curve for 25.0 ml of 0.7233 M H;PO4, with 1.256 M NaOH as the titrant, given
the following total volumes of titrant dispensed.
H3PO4 = H2PO:
Ko1 = 7.11 x 10 3
Koz = 6.32 x 10-3
Ke3 = 4.50 x 10-13
H2PO, = HPO÷²
HPO:? = PO43
V NAOH (mL): 0.00, 2.0, 12.0, 20.0, 30.0, 38.0, 45.0, 57.0, 66.0, 70.0, 85.0
Transcribed Image Text:3.) Generate a titration curve for 25.0 ml of 0.7233 M H;PO4, with 1.256 M NaOH as the titrant, given the following total volumes of titrant dispensed. H3PO4 = H2PO: Ko1 = 7.11 x 10 3 Koz = 6.32 x 10-3 Ke3 = 4.50 x 10-13 H2PO, = HPO÷² HPO:? = PO43 V NAOH (mL): 0.00, 2.0, 12.0, 20.0, 30.0, 38.0, 45.0, 57.0, 66.0, 70.0, 85.0
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