Calculate the pH of the above buffer after 10.00 mL of 1.000 M NaOH (0.01000 mol OH1) was added to 1.000 L of the buffer solution. The new concentrations are [HC2H3O2] = 0.4900 M and [C2H3O21] = 0.7100 M. The Ka = 1.60 x 105. everything is based upon the acid dissolving in water: HC2H3O2 + H20 <-> C2H3O21 + H3O*1 [ Ka = [ solve for [H30+1] then put in the numbers Ka [ [H3O*l] [H3O*1] = pH = - log a. H30*1 b. Он1 c. H2C6H6O6 d. HC6H6O61 е. HSO31 f. S032 g. H2SO3 h. HC2H3O2 i. C2H3O21 j. H2S k. HS-1 I. s2 m. HX n. X-1 О. 1 р. 2 9. 3 r. 0.5000 s. 5.5 X 10-5 t. 3.5 X 10-4 u. 8.00 x 10-5 v. 1.75 x 10-6 w. 1.11 x 108 x. 5.5 x 10-2 у. О.7000 z. 1.60 x 105 аа. 1.143 х 10-5 bb. 0.4900 сс. 1.104 х 10-5 dd. 0.7100 ее. 1.26 х 10-5 ff. 4.901 gg. 7.93 hh. 4.942 ii. 4.957

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter16: Reactions Between Acids And Bases
Section: Chapter Questions
Problem 16.54QE
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Calculate the pH of the above buffer after 10.00 mL of 1.000 M NaOH (0.01000 mol OH1) was added to 1.000 L of the
buffer solution. The new concentrations are [HC2H3O2] = 0.4900 M and [C2H3021] = 0.7100 M. The Ką = 1.60 x 105.
%3D
%3D
everything is based upon the acid dissolving in water:
HC2H3O2
+ H20
<-> C2H3O21 + H3O*1
[
Ка
solve for [H30*l] then put in the numbers
Ka [
[H30*1] =
[H3O*1] =
pH = - log
a. H30*1
b. Он1
c. H2C6H606
d. HC6H6O61
е. HSO31
f. SO3?
-2
g. H2SO3
h. HC2H3O2
i. C2H3O21
j. H2S
k. HS1
I. s2
m. HX
n. X-1
О. 1
р. 2
q. 3
r. 0.5000
s. 5.5 X 10-5
t. 3.5 X 10-4
u. 8.00 х 10-5
v. 1.75 x 10-6
w. 1.11 x 10-8
х. 5.5 х 10-2
у. О.7000
z. 1.60 x 10-5
аа. 1.143 х 10-5
bb. 0.4900
сс. 1.104 х 10-5
dd. 0.7100
ее. 1.26 х 10-5
ff. 4.901
gg. 7.93
hh. 4.942
ii. 4.957
Transcribed Image Text:Calculate the pH of the above buffer after 10.00 mL of 1.000 M NaOH (0.01000 mol OH1) was added to 1.000 L of the buffer solution. The new concentrations are [HC2H3O2] = 0.4900 M and [C2H3021] = 0.7100 M. The Ką = 1.60 x 105. %3D %3D everything is based upon the acid dissolving in water: HC2H3O2 + H20 <-> C2H3O21 + H3O*1 [ Ка solve for [H30*l] then put in the numbers Ka [ [H30*1] = [H3O*1] = pH = - log a. H30*1 b. Он1 c. H2C6H606 d. HC6H6O61 е. HSO31 f. SO3? -2 g. H2SO3 h. HC2H3O2 i. C2H3O21 j. H2S k. HS1 I. s2 m. HX n. X-1 О. 1 р. 2 q. 3 r. 0.5000 s. 5.5 X 10-5 t. 3.5 X 10-4 u. 8.00 х 10-5 v. 1.75 x 10-6 w. 1.11 x 10-8 х. 5.5 х 10-2 у. О.7000 z. 1.60 x 10-5 аа. 1.143 х 10-5 bb. 0.4900 сс. 1.104 х 10-5 dd. 0.7100 ее. 1.26 х 10-5 ff. 4.901 gg. 7.93 hh. 4.942 ii. 4.957
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