Calculate the pH of the above buffer after 10.00 mL of 1.000 M NaOH (0.01000 mol OH1) was added to 1.000 L of the buffer solution. The new concentrations are [HC2H3O2] = 0.4900 M and [C2H3O21] = 0.7100 M. The Ka = 1.60 x 105. everything is based upon the acid dissolving in water: HC2H3O2 + H20 <-> C2H3O21 + H3O*1 [ Ka = [ solve for [H30+1] then put in the numbers Ka [ [H3O*l] [H3O*1] = pH = - log a. H30*1 b. Он1 c. H2C6H6O6 d. HC6H6O61 е. HSO31 f. S032 g. H2SO3 h. HC2H3O2 i. C2H3O21 j. H2S k. HS-1 I. s2 m. HX n. X-1 О. 1 р. 2 9. 3 r. 0.5000 s. 5.5 X 10-5 t. 3.5 X 10-4 u. 8.00 x 10-5 v. 1.75 x 10-6 w. 1.11 x 108 x. 5.5 x 10-2 у. О.7000 z. 1.60 x 105 аа. 1.143 х 10-5 bb. 0.4900 сс. 1.104 х 10-5 dd. 0.7100 ее. 1.26 х 10-5 ff. 4.901 gg. 7.93 hh. 4.942 ii. 4.957
Calculate the pH of the above buffer after 10.00 mL of 1.000 M NaOH (0.01000 mol OH1) was added to 1.000 L of the buffer solution. The new concentrations are [HC2H3O2] = 0.4900 M and [C2H3O21] = 0.7100 M. The Ka = 1.60 x 105. everything is based upon the acid dissolving in water: HC2H3O2 + H20 <-> C2H3O21 + H3O*1 [ Ka = [ solve for [H30+1] then put in the numbers Ka [ [H3O*l] [H3O*1] = pH = - log a. H30*1 b. Он1 c. H2C6H6O6 d. HC6H6O61 е. HSO31 f. S032 g. H2SO3 h. HC2H3O2 i. C2H3O21 j. H2S k. HS-1 I. s2 m. HX n. X-1 О. 1 р. 2 9. 3 r. 0.5000 s. 5.5 X 10-5 t. 3.5 X 10-4 u. 8.00 x 10-5 v. 1.75 x 10-6 w. 1.11 x 108 x. 5.5 x 10-2 у. О.7000 z. 1.60 x 105 аа. 1.143 х 10-5 bb. 0.4900 сс. 1.104 х 10-5 dd. 0.7100 ее. 1.26 х 10-5 ff. 4.901 gg. 7.93 hh. 4.942 ii. 4.957
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter16: Reactions Between Acids And Bases
Section: Chapter Questions
Problem 16.54QE
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