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Calculate the potential developed by a voltaic cell using the following reaction if all dissolved species are 0.012 M at 25 °C. 2 Fe²+ (aq) + H₂O₂(aq) + 2 H+ (aq) → 2 Fe³+ (aq) + 2 H₂O (1) Acidic Solution Standard Electrode Potential, E (volts) +1.77 H₂O₂(aq) + 2 H*(aq) + 2 e 2 H₂O(l) Aut(aq) + e→→→→→→ Au(s) +1.68 Au3'(aq) + 3 e — Au(s) +1.50 Br₂(l) + 2e →→→→2 Br(aq) +1.08 NO3(aq) + 4 H*(aq) + 3 e NO(g) + 2 H₂O +0.96 Ag (aq) + e→→→→→→ Ag(s) +0.80 Hg₂2(aq) + 2 e →→→ 2 Hg(!) +0.789 +0.77 Fe³(aq) + e-Fe²(aq) Cu²+ (aq) + 2 e→→→→→→ Cu(s) HgzClz(s) + 2 et +0.337 > 2 Hg(l) + 2 Cl(aq) +0.27 Sn+(aq) + 2e →→ Sn²+ (aq) +0.15 > H₂(g) 0.00 2 H(aq) + 2 e Pb²+ (aq) + 2 e Pb(s) -0.126 Sn²(aq) + 2 e Sn(s) -0.14 Ni²+ (aq) + 2 e Ni(s) -0.25 Cd²+ (aq) + 2 e Cd(s) -0.40 Cr³+ (aq) + et -Cr²+ (aq) -0.408 Fe²(aq) + 2 e Fe(s) -0.44 Zn²+ (aq) + 2 e →→→ Zn(s) -0.763 Cr²+(aq) + 2 e Cr(s) -0.91 -1.66 A³+ (aq) + 3 e→→→→→→ Al(s) Mg2+ (aq) + 2 e Mg(s) -2.37 V Show Approach Show Tutor Steps Submit

Calculate the potential developed by a voltaic cell using the following reaction if all dissolved species are 0.012 M at 25 °C. 2 Fe²+ (aq) + H₂O₂(aq) + 2 H+ (aq) → 2 Fe³+ (aq) + 2 H₂O (1) Acidic Solution Standard Electrode Potential, E (volts) +1.77 H₂O₂(aq) + 2 H*(aq) + 2 e 2 H₂O(l) Aut(aq) + e→→→→→→ Au(s) +1.68 Au3'(aq) + 3 e — Au(s) +1.50 Br₂(l) + 2e →→→→2 Br(aq) +1.08 NO3(aq) + 4 H*(aq) + 3 e NO(g) + 2 H₂O +0.96 Ag (aq) + e→→→→→→ Ag(s) +0.80 Hg₂2(aq) + 2 e →→→ 2 Hg(!) +0.789 +0.77 Fe³(aq) + e-Fe²(aq) Cu²+ (aq) + 2 e→→→→→→ Cu(s) HgzClz(s) + 2 et +0.337 > 2 Hg(l) + 2 Cl(aq) +0.27 Sn+(aq) + 2e →→ Sn²+ (aq) +0.15 > H₂(g) 0.00 2 H(aq) + 2 e Pb²+ (aq) + 2 e Pb(s) -0.126 Sn²(aq) + 2 e Sn(s) -0.14 Ni²+ (aq) + 2 e Ni(s) -0.25 Cd²+ (aq) + 2 e Cd(s) -0.40 Cr³+ (aq) + et -Cr²+ (aq) -0.408 Fe²(aq) + 2 e Fe(s) -0.44 Zn²+ (aq) + 2 e →→→ Zn(s) -0.763 Cr²+(aq) + 2 e Cr(s) -0.91 -1.66 A³+ (aq) + 3 e→→→→→→ Al(s) Mg2+ (aq) + 2 e Mg(s) -2.37 V Show Approach Show Tutor Steps Submit

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter19: Principles Of Chemical Reactivity: Electron Transfer Reactions
Section: Chapter Questions
Problem 84GQ
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Calculate the potential developed by a voltaic cell using the following reaction if all dissolved species are 0.012 M at 25 °C. 2 Fe²+ (aq) + H₂O₂(aq) + 2 H+ (aq) → 2 Fe³+ (aq) + 2 H₂O (1) Acidic Solution Standard Electrode Potential, E (volts) +1.77 H₂O₂(aq) + 2 H*(aq) + 2 e 2 H₂O(l) Aut(aq) + e→→→→→→ Au(s) +1.68 Au3'(aq) + 3 e — Au(s) +1.50 Br₂(l) + 2e →→→→2 Br(aq) +1.08 NO3(aq) + 4 H*(aq) + 3 e NO(g) + 2 H₂O +0.96 Ag (aq) + e→→→→→→ Ag(s) +0.80 Hg₂2(aq) + 2 e →→→ 2 Hg(!) +0.789 +0.77 Fe³(aq) + e-Fe²(aq) Cu²+ (aq) + 2 e→→→→→→ Cu(s) HgzClz(s) + 2 et +0.337 > 2 Hg(l) + 2 Cl(aq) +0.27 Sn+(aq) + 2e →→ Sn²+ (aq) +0.15 > H₂(g) 0.00 2 H(aq) + 2 e Pb²+ (aq) + 2 e Pb(s) -0.126 Sn²(aq) + 2 e Sn(s) -0.14 Ni²+ (aq) + 2 e Ni(s) -0.25 Cd²+ (aq) + 2 e Cd(s) -0.40 Cr³+ (aq) + et -Cr²+ (aq) -0.408 Fe²(aq) + 2 e Fe(s) -0.44 Zn²+ (aq) + 2 e →→→ Zn(s) -0.763 Cr²+(aq) + 2 e Cr(s) -0.91 -1.66 A³+ (aq) + 3 e→→→→→→ Al(s) Mg2+ (aq) + 2 e Mg(s) -2.37 V Show Approach Show Tutor Steps Submit
Transcribed Image Text:Calculate the potential developed by a voltaic cell using the following reaction if all dissolved species are 0.012 M at 25 °C. 2 Fe²+ (aq) + H₂O₂(aq) + 2 H+ (aq) → 2 Fe³+ (aq) + 2 H₂O (1) Acidic Solution Standard Electrode Potential, E (volts) +1.77 H₂O₂(aq) + 2 H*(aq) + 2 e 2 H₂O(l) Aut(aq) + e→→→→→→ Au(s) +1.68 Au3'(aq) + 3 e — Au(s) +1.50 Br₂(l) + 2e →→→→2 Br(aq) +1.08 NO3(aq) + 4 H*(aq) + 3 e NO(g) + 2 H₂O +0.96 Ag (aq) + e→→→→→→ Ag(s) +0.80 Hg₂2(aq) + 2 e →→→ 2 Hg(!) +0.789 +0.77 Fe³(aq) + e-Fe²(aq) Cu²+ (aq) + 2 e→→→→→→ Cu(s) HgzClz(s) + 2 et +0.337 > 2 Hg(l) + 2 Cl(aq) +0.27 Sn+(aq) + 2e →→ Sn²+ (aq) +0.15 > H₂(g) 0.00 2 H(aq) + 2 e Pb²+ (aq) + 2 e Pb(s) -0.126 Sn²(aq) + 2 e Sn(s) -0.14 Ni²+ (aq) + 2 e Ni(s) -0.25 Cd²+ (aq) + 2 e Cd(s) -0.40 Cr³+ (aq) + et -Cr²+ (aq) -0.408 Fe²(aq) + 2 e Fe(s) -0.44 Zn²+ (aq) + 2 e →→→ Zn(s) -0.763 Cr²+(aq) + 2 e Cr(s) -0.91 -1.66 A³+ (aq) + 3 e→→→→→→ Al(s) Mg2+ (aq) + 2 e Mg(s) -2.37 V Show Approach Show Tutor Steps Submit
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