Calculate the SEMean Construct a 98% confidence interval for the population scores of Mrs. Paul’s students. State the null and alternate hypothesis for this test.
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Calculate the SEMean
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Construct a 98% confidence interval for the population scores of Mrs. Paul’s students.
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State the null and alternate hypothesis for this test.
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- CONSIDER that the data is UNCORRELATED use alpha .05. Provide the following: 1. CI of the F value 2. Statistical InterpretationYou obtain a t comp of .975 in a two sample independent t test with alpha at .05. Is it significant?In the population of senior students at Shermer High School, the proportion who plan to attend college is 0.64. In a random sample of 100 students from this population, the proportion who plan to attend college is 0.75. We would call the value 0.64 a P-value. z-score. parameter statistic significance level.
- The following data represent the time (in minutes) recorded for a sample of 20 employees in order to get to work using public transportation. 28 29 32 37 33 25 29 32 41 34 29 31 33 32 34 30 31 32 35 33 1) Does the sample contain any extreme values? Justify your answer with a suitable test. Comment on the results 2) According to your conclusion in part (1), calculate the best central and the best absolute dispersion measure 3) Comment on the results obtained in part (2)A random sample of 8080 eighth grade students' scores on a national mathematics assessment test has a mean score of 265265. This test result prompts a state school administrator to declare that the mean score for the state's eighth graders on this exam is more than 260260. Assume that the population standard deviation is 3030. At alphaαequals=0.140.14, is there enough evidence to support the administrator's claim? Complete parts (a) through (e).From the attached file we will conduct a hyothesis test to determine whether oxidation thickness is linearly related to tempertature. Assume significance is alpha 0.05. Null hypothesis = 0 Alternative hypothsis does not equal 0 a. employ the t-test statistic and name the sampling distribution of the test statistic. b.Should we reject the null and justify? C. use p-value to and draw the sampling distribution and shade area corresponding to p-value
- Let ?1 denote true average tread life for a premium brand of P205/65R15 radial tire, and let ?2 denote the true average tread life for an economy brand of the same size. Test H0: ?1 − ?2 = 5000 versus Ha: ?1 − ?2 > 5000 at level 0.01, using the following data: m = 45, x = 42,100, s1 = 2400, n = 45, y = 36,200, and s2 = 1800.Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value = State the conclusion in the problem context. Fail to reject H0. The data does not suggest that the difference in average tread life exceeds 5000.Reject H0. The data suggests that the difference in average tread life exceeds 5000. Fail to reject H0. The data suggests that the difference in average tread life exceeds 5000.Reject H0. The data does not suggest that the difference in average tread life exceeds 5000.Let ?1 denote true average tread life for a premium brand of P205/65R15 radial tire, and let ?2 denote the true average tread life for an economy brand of the same size. Test H0: ?1 − ?2 = 5000 versus Ha: ?1 − ?2 > 5000 at level 0.01, using the following data: m = 45, x = 42,100, s1 = 2400, n = 45, y = 36,200, and s2 = 1800. Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value = State the conclusion in the problem context. Fail to reject H0. The data does not suggest that the difference in average tread life exceeds 5000.Reject H0. The data suggests that the difference in average tread life exceeds 5000. Fail to reject H0. The data suggests that the difference in average tread life exceeds 5000.Reject H0. The data does not suggest that the difference in average tread life exceeds 5000.State the t critical value that would be used for a 99% interval based on a sample size of 37.
- Mrs. Paul wants to test that claim that, on average, her students average mark is 85. She pulls therecords of 100 of per past students over a three-year period. The grades inputted into MINITABfor analysis. Exhibit 1 below shows the results of an analysis carried out on the data obtained. Exhibit 1 One-Sample Z: Level I/IITest of mu = 85 vs mu not = 85The assumed sigma = 15.0 Variable N Mean StDev SEMean Z PStudents Score 100 75.4 12.99 * ** *** i. Calculate the SEMean ii. Construct a 98% confidence interval for the population scores of Mrs. Paul’s students.iii. State the null and alternate hypothesis for this test. iv. Calculate the missing value ** and use tables to approximate the value of ***.v. Using a 1% level of significance, state the decision criteria for this test…Mrs. Paul wants to test that claim that, on average, her students average mark is 85. She pulls therecords of 100 of per past students over a three-year period. The grades inputted into MINITABfor analysis. Exhibit 1 below shows the results of an analysis carried out on the data obtained.Exhibit 1One-Sample Z: Level I/IITest of mu = 85 vs mu not = 85The assumed sigma = 15.0 Variable N Mean StDev SE Mean Z P Students Score 100 75.4 12.99 * ** ***i. Calculate the SEMeanii. Construct a 98% confidence interval for the population scores of Mrs. Paul’s students.iii. State the null and alternate hypothesis for this test.iv. Calculate the missing value ** and use tables to approximate the value of ***v. Using a 1% level of significance, state the decision criteria for this test vi. State the conclusion for the test and whyManagers of an outdoor coffee stand in Coast City are examing the relationship between (hot) coffee sales and daily temperature, hoping to be able to predict a day's total coffee sales from the maximum temperature that day. The bivariate data values for the coffee sales (denoted by y, in dollars) and the maximum temperature (denoted by x, in degrees Fahrenheit) for each of fifteen randomly selected days during the past year are given below. These data are plotted in the scatter plot in Figure 1. The value of the sample correlation coefficient r for these data is approximately −0.649. Answer the following. Carry your intermediate computations to at least four decimal places, and round your answers as specified below. (If necessary, consult a list of formulas.) What is the value of the slope of the least-squares regression line for these data? Round your answer to at least two decimal places. What is the value of the y-intercept of the least-squares regression…