Calculate the volume of liquid in the NMR tube sketched below. Give your answer in microliters, and round to the nearest 10μL H = 2.71 cm W = 2.2 mm
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Calculate the volume of liquid in the NMR tube sketched below. Give your answer in microliters, and round to the nearest 10μL
H = 2.71 cm
W = 2.2 mm
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- Calculate the volume of liquid in the NMR tube sketched below. Give your answer in microliters, and round to the nearest 10μL . 2.7mm--width 2.87cm--Lenght μL1. What is the concentration of the dye in a solution with a percent transmittance reading of 61.6% at 570 nm? 1a. If the solution in Part 1 was made by taking 10.00 mL of a stock solution and diluting it to 100.00 mL, what is the concentration of the dye in the stock solution?A solution with a known concentration equal to 3.4 mM gave an absorbance reading of 0.820 in a spectrophotometer. Assuming that there is a linear relationship between concentration and absorbance up to a concentration of 4.0 mM, what would the absorbance reading be for a solution with a concentration 2.2 mM?
- Why must the absorbance be read at a wavelength of 543 nm?Tablet powder containing 80 mg of promazine hydrochloride is ground to a paste with 10 ml of 2 M HCl. The paste is then diluted with 200 ml of water, shaken for 15 min and finally made up to 500 ml. A portion of the extract is filtered. Then, 5 ml of the filtrate is taken and diluted to 120 ml with 0.1 M HCl. – Absorbance reading=0.755 is read at a wavelength wavelength of 251 nm – A (1%, 1 cm) value of promazine.HCl at 251 nm=935 – Stated content of promazine.HCl per tablet=50 mg – Weight of 20 tablets=1.667 g – Weight of tablet powder taken for assay=163 mg expected content in tablet taken is: A-97.78 g/mL B-97.78 g/100ml C-0.0097g/mL D-97.78 mg/100ml Concentration in diluted tablet extract is: A-0.81g/mL B-80 g/100ml C-0.00081g/mL D-0.807 mg/100ml Concentration in original tablet extract is: A-19.38g/mL B-16.15 mg/100ml C-19.38 mg/100ml D-16.15 mg/mL Amount of promazine.HCl in original extract is: A-96.90mg B-80.75mg C-96.90mg/100ml D-80.75mg/100ml…Explain the principles of UV-Vis Spectrometer
- To determine the content of Pb in a canned sausage, 5.00 g were weighed and after adequate treatment they were gauged to a volume of 100 mL, from there an aliquot of 2 mL was taken and brought to a volume of 250 mL. The readings of a series and of the sample were taken in an Atomic Absorption spectrophotometer, recording the following data: mg Pb/mL 0 1 2 3 4 Sample Absorbance 0.00 0.15 0.29 0.44 0.58 0.38 What is the% Pb in canned sausage?2. ] You make 150.0 mL of a copper(II) sulfate solution but forget to cover it before leaving for the day. The next class, you measure the volume and find that you only have 132.0 mL remaining. You didn’t record the initial concentration, but you measure the absorbance of the remaining solution at 620 nm and find that it is 0.386. You also construct the following calibration curve for CuSO4: Standard solution Abs620 0.50 M 0.424 0.40 M 0.336 0.30 M 0.247 0.20 M 0.159 (refer to image) a. What is the value for k (in Beer’s Law)? Provide a calculation or graph to support your answer. b. What is the concentration of the (remaining) solution? c. What was the concentration of the original solution from the first class? d. If you removed 7.5 mL from the 132.0 mL solution in the process of measuring the absorbance, how much water should you add to obtain the original concentration that you solved for in part (c)?Maria was tasked to determine the concentration of a Fe2(SO4)3 solution. She prepared 5 different standards of Fe2(SO4)3 using the table below as her guide. She ran the standards and the unknown solution through UV-VIS spectroscopy and recorded the absorbances of each solution. What is the concentration of the unknown solution? 0.188 M 0.296 M 0.749 M 0.857 M
- What value of absorbance corresponds to 45.0% T? If a 0.010 M solution exhibits 45.0% T at some wavelength what will be the percent transmittance for a 0.020 M solution of the same substance?You are required to measure a sample that absorbs at a wavelength of 300 nm and 4 µm.What would you use as your light source? Justify your answer.In determining the concentration of a sample X, it was found that it has maximum absorbance at 275 nm. Compound X, has molar absorptivity at 275 nm of 8400 L / mol.cm. Using a spectrophotometer with a 1 cm cuvette, an absorbance of 0.70 was found. What is the concentration of compound X in the sample?